concentration of OH to pH?

[Nathan Morgan 2C]

If given concentration of OH, how can I convert to pH?

[Janice Hu 2L]

pOH = -log [OH-]
pH = 14 - pOH

[Vashe Sundar 3H]

You can use the concentration of OH- to get the pOH, and then we can get the pH by using the relationship between pH and pOH where pH+pOH=14. If you rearrange algebraically, you'll get pH=14-pOH.

[Jessica Berejikian]

If given the OH concentration, you can convert it to the H concentration using 1x10^-14=[OH][H]. Then, find the pH by taking the -log([H]).

[KatieWu 1E]

You would first find the concentration of H+ using the equation 10^-14=[OH][H+] and then use the equation pH=-log[H+], or you could find the pOH and then subtract that from 14, since pOH and pH have to add up to 14.

[Aneesha_Nema_3C]

You have 2 options:
1. convert to pOH and then find pH: pOH = -log [OH-] --> pH = 14 - pOH
2. convert to H+ concentration and then find pH: [H+] = 1x10^-14/[OH] --> pH = -log [H+]

[005532550]

pOH and pH will always add to 14 so if you just take the log of concentration of OH and subtract it from 14 you should get pH

[Parinita Jithendra 2A]

In order to convert the concentration of OH to pH, you can first find pOH by doing -log[OH-]. Using this, you can subtract it by 14 to find pH.

[Tylina Guo 1K]

concentration of OH times concentration of H+ is equal to 1x10^-14. Use that to determine [H+], and then pH is the -log([H+]).

[HaleyC 2F]

You do -log(OH) to go get the pOH. Then to get PH you just subtract 14-pOH.

[Tristan Friet 3G]

Using the concentration of OH, you can plug it into the equation -log[OH-] = pOH, giving you the pOH. Then, knowing the relationship between pH and pOH, you would do 14 - pOH = pH, to get your pH.

[andrea tarelo 3e]

I found this diagram helpful when learning!

[Saebean Yi 3E]

The easiest way is to calculate pOH, by using -log[OH-]. Then, since pH and pOH always add to 14, just subtract the pOH by 14 and that should be the pH.

[Isamar Aburto Paniagua 2K]

pOH = -log[OH-] --> pOH - 14 = pH since pOH + pH = 14

[Kavya Anand 2B]

If given the concentration of OH, u can use the equations pOH = -log OH- and pH + pOH = 14 to convert the concentration from OH to pOH then pH.

[Ainsley McCabe 2D]

Take the negative log of the OH- concentration, and then do 14 - that number to get the pH

[Michael 1G]

If you were given an [OH-] concentration and wanted it in terms of pH you could find the pOH by taking the -log of the concentration. From there, you would need to subtract the pOH from 14 to be left with the pH.