Syllabus Problems 5H.3

[_3474001_]

Hi!

I am having difficulty approaching this problem. The table provides K but it does not match the answer given at the back of the book.

[hiranya sundar 2D]

Use the information in Table 5G.2 to determine the value of K at 300 K for the reaction 2BrCl + H2 <-> Br2 + 2HCl

The table gives us reactions H2 + Cl2 <-> 2HCl and 2BrCl <-> Br2 + Cl2.
We can add these two reactions together:
H2 + Cl2 + 2BrCl <-> 2HCl + Br2 + Cl2

And then we cancel the spectators:
H2 + Cl2+ 2BrCl <-> 2HCl + Br2 + Cl2
= 2BrCl + H2 <-> Br2 + 2HCl

Because we added the two reactions together, we can just multiply their K values to get the K value of the reaction:
4 * 10³¹ * 377.