Problem 5I #1

[kate cassiano 1F]

Hello! I'm having difficulty getting the correct answer for problem 5I #1 and am not sure why. I'm creating an ICE table and using the quadratic equation. Maybe I am missing something when calculating? If someone could explain the steps of their work that would be great!

[Ruby Stuart 1I]

Hi Kate, I plugged the 2 initial conditions that it gave us into the Kc equation, as it also gave us the value of Kc. I got (.145)^2 / (.495) (x) = .031 and multiplied both sides by x and divided both sides by .031 to get x= 1.37, which they rounded up so Br2= 1.4 mol*L-1

[Brandy_Lopez_1C]

Hello! I'm having difficulty getting the correct answer for problem 5I #1 and am not sure why. I'm creating an ICE table and using the quadratic equation. Maybe I am missing something when calculating? If someone could explain the steps of their work that would be great!

hi, for my first setup I did:
Kc= (BrCL)^2/(Cl2)(Br2) = (0.145)^2/(0.495)(x) = 0.031

And to solve for x, my setup was:
(0.031)(0.495x)=(0.145)^2
x=1.4 mol.L^-1

[kate cassiano 1F]

Okay that is very helpful! Thank you so much.