Need help with textbook question 5.39

[Sanjay Annamalai 3E]

Need help with textbook question 5.39. i keep getting 0.0164 and 0.0018 for the concentrations, not sure what I'm doing wrong

[Katie_Vaca_2B]

hi!
something that might be going wrong is that the given Kc value at 298K is wrong. Professor Lavelle has a solution manual error that gives the correct Kc value, which is 6.1 x 10^-3. Using this value we can work through the problem.
I have attached my work for the problem below, but here is an attempted explanation:
We must do two separate ice charts - one for the first equilibrium concentrations & one for when the volume is halved. Also, don’t forget to use 1/Kc since the given chemical reaction is reverse of what we plug into the ice chart (thus we use 1/(6.1 x 10^-3) = 163.93). I used the quadratic formula to find x in the first ice chart, which was 0.0065. In the second ice chart, the new initial concentration for 2(NO2) is 0.04 due to the volume being halved. We work through the ice chart once again to find the new equilibrium concentrations. The concentrations in brackets are the ones found at equilibrium.
I hope this helped :]