textbook problem 6A.23

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Nathalia Garibay 1D
Posts: 107
Joined: Fri Sep 24, 2021 7:04 am

textbook problem 6A.23

Postby Nathalia Garibay 1D » Tue Jan 31, 2023 1:15 pm

Hello,

I'm checking the solution for this problem and I'm not quite understanding how they got the value 171.36 as the denominator for .43/171.36
Any help would be appreciated!

Thanks

Stella Huang 2C
Posts: 47
Joined: Mon Jan 09, 2023 8:53 am

Re: textbook problem 6A.23

Postby Stella Huang 2C » Tue Jan 31, 2023 3:17 pm

Hi! 171.36 is the molar mass for Ba(OH)2. Since they give you the amount of Ba(OH)2 in grams, you have to divide that amount by Ba(OH)2's molar mass (171.36g/mol) to get the amount of Ba(OH)2 in moles to find the molarity.

Hope this helps!


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