reverse reaction

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505968894
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Joined: Mon Jan 09, 2023 8:59 am

reverse reaction

Postby 505968894 » Sun Feb 05, 2023 10:12 pm

when the reverse reaction is favored, is K larger or smaller than the forward reaction?

Andre Contreras 1I
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Joined: Mon Jan 09, 2023 8:30 am

Re: reverse reaction

Postby Andre Contreras 1I » Sun Feb 05, 2023 10:20 pm

When the reverse reaction is favored the K is small. This is because if the reverse reaction is favored there will be a larger concentration of the reactants at equilibrium, and since k is products over reactants a larger denominator would cause k to be smaller.

Sarah Khan
Posts: 35
Joined: Mon Jan 09, 2023 8:56 am

Re: reverse reaction

Postby Sarah Khan » Sun Feb 05, 2023 10:25 pm

If the value of K is less than 1, the reactants in the reaction are favored. If K is equal to 1, neither reactants nor products are favored.

Arielle Luong
Posts: 34
Joined: Mon Jan 09, 2023 10:14 am

Re: reverse reaction

Postby Arielle Luong » Sun Feb 05, 2023 11:20 pm

An easy way to test this during a test would be to look at your equation for Kc and plug in values for it. If equal to 1, then the reverse and forward reactions are equal. If less then one (small), the reverse reaction is favored because that means the denominator is larger then the numerator (products/ reactants) and vice versa.

Gabrielle Linden 1C
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Joined: Mon Jan 09, 2023 2:27 am

Re: reverse reaction

Postby Gabrielle Linden 1C » Sun Feb 05, 2023 11:56 pm

For small values of K, equilibrium favors the reactants. I remember it by thinking that a larger denominator will make the value of a fraction smaller. In K’s case, the denominator represents the concentration of reactants, so a high concentration of reactants at equilibrium will produce a small K value.

Valerie M Dis 2E
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Joined: Fri Sep 24, 2021 6:40 am

Re: reverse reaction

Postby Valerie M Dis 2E » Mon Feb 06, 2023 11:09 pm

When the K value is small, the reactants are favored.

Jenny Dis1D
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Joined: Mon Jan 09, 2023 2:35 am

Re: reverse reaction

Postby Jenny Dis1D » Mon Feb 06, 2023 11:10 pm

Reactants are favored when the k value is small aka less than 1.

Alex Caracalla 1I
Posts: 34
Joined: Mon Jan 09, 2023 8:27 am

Re: reverse reaction

Postby Alex Caracalla 1I » Mon Feb 06, 2023 11:15 pm

The reverse reaction is favored when K is less than 1. That means that there are more reactants (denominator) than products (numerator). If K is greater than 1, then it is the forward reaction that is favored for the opposite reasoning.

Alex Baugh 2I
Posts: 36
Joined: Mon Jan 09, 2023 9:22 am

Re: reverse reaction

Postby Alex Baugh 2I » Mon Feb 06, 2023 11:48 pm

K would typically be smaller since there would be more reactants than products if the reverse reaction was favored meaning that in the K formula, it would be less than 1 whereas if the forward reaction was favored, then there would be more products than reactants and K would be greater than 1.

Isabelle Kim 3E
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Re: reverse reaction

Postby Isabelle Kim 3E » Tue Feb 07, 2023 1:37 am

When the reverse rxn is being favored, then that would mean that the formation of reactants are favored over that of products. And because of this, the concentration of reactants increases, which explains why the K value decreases since remember that K is the ratio between products and reactants. Reactants are in the denominator.

Megan Wang 3D
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Joined: Mon Jan 09, 2023 9:55 am

Re: reverse reaction

Postby Megan Wang 3D » Tue Feb 07, 2023 9:12 am

If the reverse reaction if favored, it means that the concentration of reactants is higher than that of the products, so K would be small.

Jinhee Lee 3B
Posts: 35
Joined: Mon Jan 09, 2023 9:47 am

Re: reverse reaction

Postby Jinhee Lee 3B » Sun Feb 19, 2023 10:32 pm

Hi! When the reverse reaction is favored, K is smaller. Reverse reaction is favored whenever there is a lot of reactants, meaning the reaction will go towards the reactants to decrease it and go back to equilibrium. Since K is calculated by [P]/[R], a big R concentration will make K smaller. The bigger the denominator, the smaller the K.


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