## Chemical Equilibrium Part 2 Post-Module #19 & 27

JennyCKim1J
Posts: 51
Joined: Fri Sep 29, 2017 7:04 am

### Chemical Equilibrium Part 2 Post-Module #19 & 27

19. Calculate the reaction quotient, QC, from the following equilibrium data collected in a 3.00 L sealed reaction vessel for the reaction: AsH3 (g) ⇌ As (s) + H2 (g)
AsH3 = 5.55 x 10-4 mol, As = 3.31 x 10-3 mol, H2 = 1.23 x 10-3 mol.

First I divided given mols with 3.00L to find mol*L-1 and did what I would do to find K, but I am not getting the right answer. What am I doing wrong?

27. A mixture of 2.5 moles H2O and 100 g of C are placed in a 50 L container and allowed to come to equilibrium subject to the following reaction:
C(s) + H2O (g) ⇌ CO (g) + H2 (g)
The equilibrium concentration of hydrogen is found to be [H2] = 0.040 M. What is the equilibrium concentration of water, [H2O]?

I need help with this q as well!

Lucian1F
Posts: 87
Joined: Fri Sep 29, 2017 7:07 am
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### Re: Chemical Equilibrium Part 2 Post-Module #19 & 27

Did you make sure to omit the solid molecule from the calculations? Solids are not included in equilibrium constant equations

Sohini Halder 1G
Posts: 58
Joined: Thu Jul 13, 2017 3:00 am
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### Re: Chemical Equilibrium Part 2 Post-Module #19 & 27

Balance the equation. The coefficients change how you raise the numbers to a power. You are likely messing up there.