ICE Box

Moderators: Chem_Mod, Chem_Admin

Kassandra Molina 2B
Posts: 43
Joined: Wed Nov 16, 2016 3:03 am

ICE Box

Postby Kassandra Molina 2B » Tue Nov 28, 2017 8:43 pm

When determining the change in pressure, how do you know whether the "x" will be positive or negative? What determines this?

Ryan Sydney Beyer 2B
Posts: 82
Joined: Fri Sep 29, 2017 7:07 am
Been upvoted: 1 time

Re: ICE Box

Postby Ryan Sydney Beyer 2B » Tue Nov 28, 2017 8:56 pm

If the reaction is going to the right then the products will gain some partial pressure so it will be a positive x value for the product and a negative x value for the reactants. The same is true for the opposite in which a reaction going to the left should have a negative x value for the products and a positive x value for the reactants.

Gobinder Pandher 3J
Posts: 21
Joined: Fri Sep 29, 2017 7:07 am

Re: ICE Box

Postby Gobinder Pandher 3J » Sun Dec 03, 2017 9:05 pm

If the question gives you the pressures for all of the substances in the reaction (both the reactants and products), calculate Q and compare Q to K. If Q > K then X will be negative for the products and positive for the reactants as the reaction favors the formation of reactants. If Q < K then X will be positive for your products and negative for your reactants as the reaction favors the formation of products.

JonathanLam1G
Posts: 25
Joined: Fri Sep 29, 2017 7:04 am

Re: ICE Box

Postby JonathanLam1G » Sun Dec 03, 2017 9:39 pm

You have to calculate Q first.
If Q < 1, then you subtract from the reactants as products are forming. If Q > 1, then you add to the reactants!


Return to “Non-Equilibrium Conditions & The Reaction Quotient”

Who is online

Users browsing this forum: No registered users and 1 guest