homework problem 11.89

Moderators: Chem_Mod, Chem_Admin

Amanda Hagen 1L
Posts: 26
Joined: Fri Sep 29, 2017 7:04 am

homework problem 11.89

Postby Amanda Hagen 1L » Mon Dec 04, 2017 9:39 pm

In problem 11.89 of the homework, how do we find the balanced chemical equation for part a?

Chem_Mod
Posts: 17827
Joined: Thu Aug 04, 2011 1:53 pm
Has upvoted: 405 times

Re: homework problem 11.89

Postby Chem_Mod » Tue Dec 05, 2017 12:51 am

Compare the partial pressures at time=0 to time=at the end of that graph. A decreases over time, so that must be reactant. With same logic, B and C increase, so they must be products. A and C change by the same amount of pressure roughly, so A:C must be 1:1. C changes twice the amount of B, so B:C must be 1:2. With this information, you can figure out that 2A --> B + 2C.

Amanda Hagen 1L
Posts: 26
Joined: Fri Sep 29, 2017 7:04 am

Re: homework problem 11.89

Postby Amanda Hagen 1L » Tue Dec 05, 2017 11:20 am

Thank you! That was very helpful.


Return to “Non-Equilibrium Conditions & The Reaction Quotient”

Who is online

Users browsing this forum: No registered users and 1 guest