example in class

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FrankieClarke2C
Posts: 59
Joined: Fri Sep 28, 2018 12:28 am

example in class

Postby FrankieClarke2C » Wed Jan 09, 2019 3:08 pm

For the ADP example in class, to get the final EQ concentration for the ADP and Pi did he just subtract final from initial to get the concentration?

Katie Frei 1L
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

Re: example in class

Postby Katie Frei 1L » Wed Jan 09, 2019 3:12 pm

Using the ICE box he subtracted the initial molarity from the equilibrium molarity to find the change in molarity.

KatrinaPho_2I
Posts: 60
Joined: Fri Sep 28, 2018 12:28 am

Re: example in class

Postby KatrinaPho_2I » Wed Jan 09, 2019 3:24 pm

He simply set up an ICE table with the provided information and the assumption that the initial concentrations of AD and Pi were 0 initially. With the initial and equilibrium concentrations of ADP provided in the problem, he calculated the change in concentration for ADP. Because the molar ratios of all reactants and products were 1:1, we can assume that the concentrations of both AD and Pi changed by the same amount. This gives you the equilibrium molarity of all reactants and products.

2c_britneyly
Posts: 62
Joined: Fri Sep 28, 2018 12:16 am

Re: example in class

Postby 2c_britneyly » Wed Jan 09, 2019 4:01 pm

For this example, the mole ratios of ADP to AD and ADP to Pi are 1, so the change in moles of products is the same as change in moles of reactants. If the mole ratios were different, you would have to multiply by stoichiometric coefficients before finding equilibrium concentrations.


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