11.41 in 6th edition

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Alexa Tabakian 1A
Posts: 38
Joined: Fri Sep 28, 2018 12:20 am

11.41 in 6th edition

Postby Alexa Tabakian 1A » Wed Jan 09, 2019 5:13 pm

I was wondering how to set up the ICE table for this reaction. Do we have to convert into mol/L? Also do we assume that we start with no NH3 or CO2?

Eshwar Venkat 1F
Posts: 32
Joined: Fri Sep 28, 2018 12:22 am

Re: 11.41 in 6th edition

Postby Eshwar Venkat 1F » Wed Jan 09, 2019 5:20 pm

Yes, the reaction starts with no NH3 or CO2. For the equilibrium values, you need to convert the 17.4 mg of CO2 to moles and divide by the volume of the container to get molarity, and multiply that by 2 to get the molarity of NH3.


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