Converting Qc to Qp [ENDORSED]

[Joon Chang 2F]

I know that Q is calculated in the same way as K, so does that mean conversions are done the same way using P=(conc.)RT?

[LorenzoDuvergne3I]

Q is essentially the same thing as K, just not at equilibrium, so yes it should be the same formula. Does anybody know if it will be given to us?

[Alma Flores 1D]

Would it be the same as K=[products]/[reactants]?

[Andrew Bennecke]

Q and K are calculated the same way. They are essentially the same value, except K is the equilibrium constant while Q's relation to K indicates whether the forard or reverse reaction will be favored until Q=K. Also, I believe that we will either be given the K value, or the means to calculate it.

[Victor Qiu 1C]

The way to calculate K_c and Q_c is very similar. Both are the relative ratio of products to reactants. The only difference is that K_c is the relative ratio of products to reactants when the reaction is at equilibrium, while Q_c is the relative ratio of products to reactants at a given instant (the reaction might not be at equilibrium). Thus, converting Q_c to Q_P is similar to converting K_c to K_P.

K_P=(RT)^ΔnK_c, Δn=n_Products-n_Reactants

Q_P=(RT)^ΔnQ_c, Δn=n_Products-n_Reactants