Reaction Quotient Value

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Chris Dis3L
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Joined: Fri Sep 28, 2018 12:25 am

Reaction Quotient Value

Postby Chris Dis3L » Sun Jan 13, 2019 11:44 pm

As we learned, if at some time during a reaction, the reaction quotient, Q, is less than K then the forward reaction is favored. If Q is greater than K then the reverse reaction is favored. However, what happens if Q is equal to K? Does that just mean that the same amount of reactants and products are formed?

emily gao 1C
Posts: 61
Joined: Fri Sep 28, 2018 12:29 am

Re: Reaction Quotient Value

Postby emily gao 1C » Sun Jan 13, 2019 11:45 pm

if q = k then the reaction is at equilibrium

Laura Gong 3H
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Re: Reaction Quotient Value

Postby Laura Gong 3H » Mon Jan 14, 2019 2:48 pm

When Q=K, the reaction is at equilibrium; neither the product or reactant side is favored.

Gillian Murphy 2C
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Joined: Fri Sep 28, 2018 12:22 am

Re: Reaction Quotient Value

Postby Gillian Murphy 2C » Mon Jan 14, 2019 2:51 pm

If Q is equal to K, that means that the concentrations at the time we are evaluating are equal to the concentrations found when the reaction is in equilibrium. This means that the reaction is in equilibrium, so neither reaction is favored because at equilibrium, the forward and reverse reactions occur at the same rate.

Carine Tamamian 2B
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Joined: Fri Sep 28, 2018 12:23 am

Re: Reaction Quotient Value

Postby Carine Tamamian 2B » Mon Jan 14, 2019 4:23 pm

If Q < K, then [R] > [P] and forward reaction is favored
If Q > K, then [R] < [P] and reverse reaction is favored
Q=K then reaction is at equilibrium

Jake Gordon 1A
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Joined: Fri Sep 28, 2018 12:15 am

Re: Reaction Quotient Value

Postby Jake Gordon 1A » Mon Jan 14, 2019 7:46 pm

This would mean that the reaction is already at equilibrium and the concentrations of the products and the reactants are unchanging even though movement in each direction may still occur. At this point Q would not even exist and we would call it K. It's just a notation technicality but at a given temperature when Q equals K, Q ceases to exist and it is just K the equilibrium constant.


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