12.23 in sixth edition

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Alexa Tabakian 1A
Posts: 38
Joined: Fri Sep 28, 2018 12:20 am

12.23 in sixth edition

Postby Alexa Tabakian 1A » Mon Jan 14, 2019 9:13 pm

I'm confused on how to set up the equation to get H30+ if we are only given one number which is Kw. Can someone please explain?

ChathuriGunasekera1D
Posts: 78
Joined: Fri Sep 28, 2018 12:17 am

Re: 12.23 in sixth edition

Postby ChathuriGunasekera1D » Mon Jan 14, 2019 9:18 pm

Given Kw of 2.1 10^-14, you know that [H3O+] and [OH-] have to be the same because water is neutral so one cannot be greater than the other. So the [H3O+] and [OH-] is the square root of Kw


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