Page 1 of 1

12.23 in sixth edition

Posted: Mon Jan 14, 2019 9:13 pm
by Alexa Tabakian 1A
I'm confused on how to set up the equation to get H30+ if we are only given one number which is Kw. Can someone please explain?

Re: 12.23 in sixth edition

Posted: Mon Jan 14, 2019 9:18 pm
by ChathuriGunasekera1D
Given Kw of 2.1 10^-14, you know that [H3O+] and [OH-] have to be the same because water is neutral so one cannot be greater than the other. So the [H3O+] and [OH-] is the square root of Kw