5I.35 7th edition

Moderators: Chem_Mod, Chem_Admin

Katie Frei 1L
Posts: 64
Joined: Fri Sep 28, 2018 12:27 am

5I.35 7th edition

Postby Katie Frei 1L » Tue Jan 15, 2019 11:37 am

Does anyone know why for problem 5I.35 in the 7th edition of the textbook the p in the numerator of the correct equilibrium relation is squared? Does it have to do with setting up the ICE box?

Olivia L 4E
Posts: 59
Joined: Fri Sep 28, 2018 12:23 am
Been upvoted: 1 time

Re: 5I.35 7th edition

Postby Olivia L 4E » Tue Jan 15, 2019 11:49 am

It is squared because the equilibrium equation is [N2][O2]/[NO2]^2. The change in concentration is denoted as p. Because N2 and O2 began with zero initial concentration, you simply use 0+p to get p as the equilibrium concentrations for both. The problem simplified it further by substituting the p in as the concentrations for N2 and O2 which is p x p, thus p^2.

Return to “Non-Equilibrium Conditions & The Reaction Quotient”

Who is online

Users browsing this forum: No registered users and 1 guest