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11.33 6th edition

Posted: Tue Jan 15, 2019 4:09 pm
by CaminaB_1D
11.33 A 0.500-L reaction vessel at 700. K contains 1.20 mmol SO2(g), 0.50 mmol O2(g), and 0.10 mmol SO3(g). At 700. K, Kc 1.7 106 for the equilibrium 2 SO2(g) O2(g) ∆ 2 SO3(g). (a) Calculate the reaction quotient Qc. (b) Will more SO3(g)
tend to form?

Why do we divide each elements moles by the volume of the reaction vessel when calculating for the reaction quotient

Re: 11.33 6th edition

Posted: Tue Jan 15, 2019 4:14 pm
by Elizabeth Gallmeister 1A
In order to calculate the reaction quotient, we need molarities, or concentrations of the products and reactants. We know that concentration is a measure of number of moles divided by volume, so we do just that: put moles over volume to find molarity of each.

Re: 11.33 6th edition

Posted: Tue Jan 15, 2019 11:53 pm
by Chloe Likwong 2K
Similar to finding the equilibrium constant, the reaction quotient requires you to use molarity/concentration.