ignoring x validity

[marcus lin 1E]

so if we ignore x and it isn't less than 5% of the original molarity and is therefore invalid, do we just continue to calculate x quadratically?

[BenJohnson1H]

precisely, unless it is a cubic in which you would have three possible values of X. Then plug the values in to see which value is viable

[chaggard]

Yes, because anything over 5% alters the value for x. So your answer would be slightly off.

[Xingzheng Sun 2K]

That is what we are supposed to do. The formula to calculate x is given on the formula sheet, and it always works for solving the x.

[Kavvya Gupta 1H]

you only ignore the x generally when x<10^-3. Usually, x will be less than 5%, but if it isn't then you would do quadratic as your answer would be slightly off otherwise.

[taryn_baldus2E]

You can also check to see if it was okay to make this approximation by calculating the value for x by the original concentration and multiplying by 100 to see if it was truly less than 5%.

[Shibhon_Shepard]

But are they going to give us a problem that is x^3?