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question 5i.19

Posted: Thu Jan 24, 2019 10:08 pm
by Athena L 1B
Can someone explain this question?
A reaction mixture that consisted of 0.400 mol H2 and 1.60 mol I2 was introduced into a flask of volume 3.00 L and heated. At equilibrium, 60% of the hydrogen gas had reacted. What is the equilibrium constant K for the reaction H2(g) + I2(g) <=> 2HI(g) at this temp?

Re: question 5i.19

Posted: Thu Jan 24, 2019 10:16 pm
by Chem_Mod
Set up an ice table and the change is given (60% is reacted) you can find the equilibrium concentration for all the gas and calculate K

Re: question 5i.19

Posted: Fri Jan 25, 2019 3:13 pm
by Ethan Breaux 2F
Don't forget to use c = n/V and that at equilibrium 40% of hydrogen is left.

Re: question 5i.19

Posted: Sun Jan 27, 2019 12:14 am
by Cade Okohira 4K
First, you would need to convert the mol amounts into molarity, or mol/L by dividing the mol amounts by the amount of L, which is 3 L. Then, you can create an ICE table, knowing that 60% of the H2 had converted into product. Then, you can find Kc by calculating [HI]^2/[H2][I2].