Situations in which Q=K

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Ritu Gaikwad 2E
Posts: 52
Joined: Thu Jul 11, 2019 12:16 am

Situations in which Q=K

Postby Ritu Gaikwad 2E » Sun Jan 12, 2020 2:01 pm

What reactions describe when Q=K or is a reaction even present when there is the same amount of product and reactant?

KarineKim2L
Posts: 100
Joined: Fri Aug 30, 2019 12:16 am

Re: Situations in which Q=K

Postby KarineKim2L » Sun Jan 12, 2020 2:04 pm

When Q=K, the reaction is at equilibrium, so the forward reaction is occurring at the same rate as the backward reaction.

Delaney Smith 1C
Posts: 52
Joined: Thu Feb 28, 2019 12:15 am

Re: Situations in which Q=K

Postby Delaney Smith 1C » Sun Jan 12, 2020 4:33 pm

The reaction is still present and occurring even when the products are equal to the reactants. This just means that P/R ratio is the same so there won't be more products or reactants as the reaction is at equilibrium.

Emil Velasco 1H
Posts: 96
Joined: Wed Nov 21, 2018 12:19 am

Re: Situations in which Q=K

Postby Emil Velasco 1H » Sun Jan 12, 2020 4:50 pm

When Q=K, then the reaction is at equilibrium

705367472
Posts: 22
Joined: Tue Nov 19, 2019 12:19 am

Re: Situations in which Q=K

Postby 705367472 » Sun Jan 12, 2020 5:46 pm

Pretty much if Q is equal to K that is how you know the equation is at equilibrium.

405268063
Posts: 102
Joined: Thu Jul 25, 2019 12:17 am

Re: Situations in which Q=K

Postby 405268063 » Sun Jan 12, 2020 6:02 pm

If Q=K, as everybody has been saying, you know the equation has reached its equilibrium. However, K really is the right way to label the ratio of reactants to products at equilibrium.

William Chan 1D
Posts: 102
Joined: Sat Sep 14, 2019 12:15 am

Re: Situations in which Q=K

Postby William Chan 1D » Sun Jan 12, 2020 6:22 pm

If Q = K, then the reaction is at equilibrium.

Emily Burghart 1k
Posts: 50
Joined: Wed Sep 18, 2019 12:17 am

Re: Situations in which Q=K

Postby Emily Burghart 1k » Sun Jan 12, 2020 9:44 pm

When Q=K the reaction is at equilibrium meaning that the forward and reverse reactions are happening at the same rate. This does not mean that they are not occurring, but rather [R] and [P] are being formed at the same time, and neither is being formed more than the other.


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