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### Situations in which Q=K

Posted: Sun Jan 12, 2020 2:01 pm
What reactions describe when Q=K or is a reaction even present when there is the same amount of product and reactant?

### Re: Situations in which Q=K

Posted: Sun Jan 12, 2020 2:04 pm
When Q=K, the reaction is at equilibrium, so the forward reaction is occurring at the same rate as the backward reaction.

### Re: Situations in which Q=K

Posted: Sun Jan 12, 2020 4:33 pm
The reaction is still present and occurring even when the products are equal to the reactants. This just means that P/R ratio is the same so there won't be more products or reactants as the reaction is at equilibrium.

### Re: Situations in which Q=K

Posted: Sun Jan 12, 2020 4:50 pm
When Q=K, then the reaction is at equilibrium

### Re: Situations in which Q=K

Posted: Sun Jan 12, 2020 5:46 pm
Pretty much if Q is equal to K that is how you know the equation is at equilibrium.

### Re: Situations in which Q=K

Posted: Sun Jan 12, 2020 6:02 pm
If Q=K, as everybody has been saying, you know the equation has reached its equilibrium. However, K really is the right way to label the ratio of reactants to products at equilibrium.

### Re: Situations in which Q=K

Posted: Sun Jan 12, 2020 6:22 pm
If Q = K, then the reaction is at equilibrium.

### Re: Situations in which Q=K

Posted: Sun Jan 12, 2020 9:44 pm
When Q=K the reaction is at equilibrium meaning that the forward and reverse reactions are happening at the same rate. This does not mean that they are not occurring, but rather [R] and [P] are being formed at the same time, and neither is being formed more than the other.