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Posted: Sun Jan 19, 2020 5:28 pm
by Johnathan Smith 1D
Does anyone know how to start number 19? It says only 60 percent of the hydrogen reaction, but I’m not really sure what to do with that.

Re: 5I.19

Posted: Sun Jan 19, 2020 6:40 pm
by Christine Honda 2I
Since we know that 60% of the H2 reacted, then at equilibrium we can use the fact that there will be 40% left when solving for the equilibrium concentrations. Therefore, when we use the ICE table, we can set the change in H2 (0.133-x) equal to the equilibrium value of H2 (0.4 x 0.133) and solve for X!