Posted: Sun Jan 19, 2020 5:28 pm
Does anyone know how to start number 19? It says only 60 percent of the hydrogen reaction, but I’m not really sure what to do with that.
Posted: Sun Jan 19, 2020 6:40 pm
Since we know that 60% of the H2 reacted, then at equilibrium we can use the fact that there will be 40% left when solving for the equilibrium concentrations. Therefore, when we use the ICE table, we can set the change in H2 (0.133-x) equal to the equilibrium value of H2 (0.4 x 0.133) and solve for X!