q vs k

Moderators: Chem_Mod, Chem_Admin

connie 2C
Posts: 106
Joined: Thu Jul 11, 2019 12:17 am

q vs k

Postby connie 2C » Mon Jan 20, 2020 12:27 am

will the q value eventually reach k? is q the value that is calculated when the reaction is not at equilibrium?

Naneeta Desar 1K
Posts: 106
Joined: Fri Aug 09, 2019 12:15 am

Re: q vs k

Postby Naneeta Desar 1K » Mon Jan 20, 2020 12:35 am

Yes Q is the value calculated when the reaction is not at equilibrium.

VLi_2B
Posts: 99
Joined: Sat Sep 14, 2019 12:15 am

Re: q vs k

Postby VLi_2B » Mon Jan 20, 2020 12:46 am

Q is the reaction quotient and expresses the relative ratio of products to reactants at a given instant. On the other hand, K is the equilibrium constant and is used to calculate the final concentrations at equilibrium for a reaction using an ICE table. If Q and K equal each other, the reaction is at equilibrium.

Ian Morris 3C
Posts: 101
Joined: Wed Sep 18, 2019 12:18 am

Re: q vs k

Postby Ian Morris 3C » Mon Jan 20, 2020 3:26 am

When Q reaches K, it is at equilibrium.

Mitchell Koss 4G
Posts: 128
Joined: Sat Jul 20, 2019 12:17 am

Re: q vs k

Postby Mitchell Koss 4G » Mon Jan 20, 2020 7:56 am

Yes if a reaction reaches equilibrium, it will have Q=K

Christineg1G
Posts: 115
Joined: Fri Aug 09, 2019 12:15 am
Been upvoted: 1 time

Re: q vs k

Postby Christineg1G » Mon Jan 20, 2020 9:28 am

Yes, when Q=K the solution has reached its equilibrium composition and doesn't change in either direction.

Lauren Tanaka 1A
Posts: 109
Joined: Sat Aug 17, 2019 12:18 am

Re: q vs k

Postby Lauren Tanaka 1A » Mon Jan 20, 2020 6:09 pm

Yes Q is just the value of equilibrium at any given point and K is the equilibrium constant. When Q and K are equal, that would show you that the reaction is at equilibrium.

505306205
Posts: 97
Joined: Thu Jul 25, 2019 12:15 am
Been upvoted: 1 time

Re: q vs k

Postby 505306205 » Mon Jan 20, 2020 6:09 pm

Q value is calculated when you don't know whether the reaction is at equilibrium or not. If Q equals K, then the reaction is at equilibrium.

Joowon Seo 3A
Posts: 100
Joined: Sat Aug 24, 2019 12:17 am
Been upvoted: 1 time

Re: q vs k

Postby Joowon Seo 3A » Mon Jan 20, 2020 6:20 pm

The q value will eventually reach k given a long period of time, because that's where the reaction occurs at equilibrium.

aishwarya_atmakuri
Posts: 101
Joined: Sat Jul 20, 2019 12:15 am

Re: q vs k

Postby aishwarya_atmakuri » Mon Jan 20, 2020 6:34 pm

Q represents the current state of the system but K is the equilibrium state. Eventually, Q will go towards K.

Asia Yamada 2B
Posts: 97
Joined: Wed Sep 30, 2020 9:36 pm

Re: q vs k

Postby Asia Yamada 2B » Tue Jan 12, 2021 1:10 pm

Yes, Q is the reaction quotient that is calculated at any point in time during the reaction. You can compare Q to K to determine which way the reaction will proceed to eventually establish equilibrium where Q=K.

reyvalui_3g
Posts: 85
Joined: Wed Sep 30, 2020 9:52 pm

Re: q vs k

Postby reyvalui_3g » Tue Jan 12, 2021 8:04 pm

Q is the reaction quotient for any specific moment during a reaction, technically Q does not approach K but the concentrations of the reactant and products will change so that the ratio will be equal to K.

alebenavides
Posts: 117
Joined: Wed Sep 30, 2020 9:39 pm

Re: q vs k

Postby alebenavides » Wed Jan 13, 2021 12:06 pm

basically once Q reaches K it reaches the equilibrium needed.

Becca Nelson 3F
Posts: 103
Joined: Wed Sep 30, 2020 9:52 pm

Re: q vs k

Postby Becca Nelson 3F » Wed Jan 13, 2021 12:49 pm

Q should reach K if the reaction is left alone. Once Q equals K the reaction is at equilibrium and the forward and reverse rates of the reaction are the same. If Q > K more reactants will be formed and if Q<K more products will be formed until these values are the same.

Aayushi Jani 3A
Posts: 104
Joined: Wed Sep 30, 2020 9:51 pm

Re: q vs k

Postby Aayushi Jani 3A » Wed Jan 13, 2021 12:54 pm

Q is the reaction quotient (taken at any time during the reaction). If you let the reaction go until it reaches equilibrium, Q should equal K (since K is the equilibrium constant).

Morgan Gee 3B
Posts: 95
Joined: Wed Sep 30, 2020 9:48 pm

Re: q vs k

Postby Morgan Gee 3B » Wed Jan 13, 2021 2:38 pm

Q is the reaction quotient which is the concentration of products to the concentration of reactants raised to their coefficients. Q can be less than K, greater than K, and equal to K. When Q is less than K, that means there are more reactants than products and the forward reaction needs to occur at a greater rate to reach equilibrium. When Q is greater than K, that means there are more products than reactants and the reverse reaction needs to occur at a greater rate to reach equilibrium. When Q equals K, the reaction is at equilibrium.

Ava Nickman
Posts: 100
Joined: Wed Sep 30, 2020 9:54 pm

Re: q vs k

Postby Ava Nickman » Wed Jan 13, 2021 3:09 pm

yes k and q are the same but k represents the ratio at equilibrium and and q represents other points in the reaction

VincentLe_3A
Posts: 96
Joined: Wed Sep 30, 2020 10:01 pm

Re: q vs k

Postby VincentLe_3A » Wed Jan 13, 2021 3:19 pm

Yes, q will eventually reach k after letting the reaction take place over time. Q is finding the ratio at a certain time during the reaction, which could be greater than, less than, or equal to k. If the q is equal to k, then the reaction is at equilibrium. However, if q<k, that means there are more reactants in the ratio compared to the equilibrium constant ratio, so the reaction will form more products so that the equilibrium constant is reached. Same applies when q>k, which means there are more products in the ratio, so the reaction will form more reactants so that the equilibrium constant is attained.

Lorraine Jiang 2C
Posts: 102
Joined: Wed Sep 30, 2020 9:54 pm
Been upvoted: 1 time

Re: q vs k

Postby Lorraine Jiang 2C » Thu Jan 14, 2021 12:13 am

Hi! The reaction quotient basically represents the concentration of production to reactant at any given time in the reaction. However, K specifically implies the ratio at equilibrium.

Hope it helps!

Lauren To 1E
Posts: 47
Joined: Fri Dec 11, 2020 12:17 am

Re: q vs k

Postby Lauren To 1E » Thu Jan 14, 2021 2:01 pm

Yes, Q=K once the reaction is at equilibrium. We use Q for calculations when we're unsure if the reaction has reached equilibrium.

Jason Knight - 1F
Posts: 107
Joined: Wed Sep 30, 2020 9:55 pm

Re: q vs k

Postby Jason Knight - 1F » Thu Jan 14, 2021 2:06 pm

Q, the reaction quotient, tells us the [p]/[r] ratio at any point in the reaction. The value of Q then tells us if our reaction is at equilibrium if (Q=K). If K>Q, then the forward reaction is favored, and if K<Q, then the reverse reaction is favored. We use Q when we are not sure if the reaction is at equilibrium or not.

Ivy Tan 1E
Posts: 95
Joined: Wed Sep 30, 2020 10:09 pm
Been upvoted: 2 times

Re: q vs k

Postby Ivy Tan 1E » Fri Jan 15, 2021 11:53 am

Hi!
Q is the reaction quotient, or the ratio of products to reactants at any given point in the reaction. Q may equal K (when the reaction is at equilibrium) or it may higher or lower than K (when the reaction is not at equilibrium). If Q is higher than K, the reaction favors the reactants. If Q is lower than K, the reaction favors the products. Hope this helps!!

Melis Kasaba 2B
Posts: 91
Joined: Wed Sep 30, 2020 9:49 pm

Re: q vs k

Postby Melis Kasaba 2B » Fri Jan 15, 2021 12:50 pm

Q is the reaction quotient and can be used to figure out which direction the reaction will shift in order to reach equilibrium.

K > Q: reaction proceeds forward, R --> P.
K < Q: reaction proceeds in reverse direction, P --> R.
Q = K: system is at equilibrium, no shift to either left or right

Rob Tsai 2F
Posts: 94
Joined: Wed Sep 30, 2020 10:09 pm

Re: q vs k

Postby Rob Tsai 2F » Sat Jan 16, 2021 4:23 am

I don't know if this right, but I like to think of Q as any random moment in time during my life, and K as my home. I could be out and about at school, hitting the town on a Saturday night, or watching TV on my couch (pre/post quarantine of course). Q can either be greater than, less than, or equal to K. It all depends on what "moment" you choose (what concentrations/partial pressures) you are given. Sorry if that didn't make sense, I'm feeling kind of poetic today.

Nina Fukui 2J
Posts: 96
Joined: Wed Sep 30, 2020 9:43 pm

Re: q vs k

Postby Nina Fukui 2J » Sat Jan 16, 2021 6:55 am

they're both the same calculation method but the letter q usually means the solution isn't at equilibrium. but eventually q should reach k after a certain period of time

Navdha Sharma 3J
Posts: 96
Joined: Wed Sep 30, 2020 9:46 pm

Re: q vs k

Postby Navdha Sharma 3J » Sat Jan 16, 2021 10:31 am

Q and K are calculated in the same way but Q is the calculation that is not done at equilibrium.

Mingzi Yang 1E
Posts: 90
Joined: Wed Sep 30, 2020 9:53 pm

Re: q vs k

Postby Mingzi Yang 1E » Sat Jan 16, 2021 11:22 pm

If Q equals K, the reaction is at equilibrium. Q is calculated the same way as K when the reaction is not at equilibrium.

Karen Elrayes 1L
Posts: 91
Joined: Wed Sep 30, 2020 9:45 pm

Re: q vs k

Postby Karen Elrayes 1L » Sun Jan 17, 2021 2:16 am

Q calculates the ratio of products to reactants at anyone point not just equilibrium.

David Jen 1J
Posts: 96
Joined: Wed Sep 30, 2020 9:33 pm

Re: q vs k

Postby David Jen 1J » Sun Jan 17, 2021 2:29 am

Q calculates the same way as K, but Q calculates at concentrations that aren't equilibrium.

Gicelle Rubin 1E
Posts: 81
Joined: Fri Oct 02, 2020 12:16 am

Re: q vs k

Postby Gicelle Rubin 1E » Sun Jan 17, 2021 4:24 am

Melis Kasaba 2B wrote:Q is the reaction quotient and can be used to figure out which direction the reaction will shift in order to reach equilibrium.

K > Q: reaction proceeds forward, R --> P.
K < Q: reaction proceeds in reverse direction, P --> R.
Q = K: system is at equilibrium, no shift to either left or right


Thank you for making it easy to understand :)

Will Skinner
Posts: 84
Joined: Wed Sep 30, 2020 9:28 pm

Re: q vs k

Postby Will Skinner » Sun Jan 17, 2021 8:11 am

Yes q will eventually reach k if the temperature remains the same. Also I think of q as a ratio that changes as the reaction continues and becomes equal to k when the reaction “finishes”.

Uyen Trinh 3C
Posts: 51
Joined: Thu Nov 14, 2019 12:17 am

Re: q vs k

Postby Uyen Trinh 3C » Sun Jan 17, 2021 8:47 am

At equilibrium, Q=K. When the value of Q is not the same as the value of Kc, the reaction is not at equilibrium.

Additionally, when Q is less than Kc, the reaction will shift to form more products to reach equilibrium. Vice versa, when Q is more than Kc, the reaction will shift to form more reactants to reach equilibrium.

So eventually if you wait long enough Q=K.

OmarArafat_2K
Posts: 41
Joined: Thu Dec 17, 2020 12:17 am

Re: q vs k

Postby OmarArafat_2K » Sun Jan 17, 2021 9:50 am

Yes, it will eventually. Q is the current state reaction quotient and K is the equilibrium constant. Q will eventually reach equilibirum.

Chinmayi Mutyala 3H
Posts: 95
Joined: Wed Sep 30, 2020 9:50 pm

Re: q vs k

Postby Chinmayi Mutyala 3H » Sun Jan 17, 2021 2:39 pm

If Q = K, the reaction is at equilibrium.

Shivani Kapur 2J
Posts: 95
Joined: Wed Sep 30, 2020 9:59 pm

Re: q vs k

Postby Shivani Kapur 2J » Sun Jan 17, 2021 2:53 pm

When Q = K, the reaction is at equilibrium. K will only change with a temperature change, but Q will change depending on factors such as changes in concentration and pressure.

Rose_Malki_3G
Posts: 127
Joined: Wed Sep 30, 2020 10:02 pm

Re: q vs k

Postby Rose_Malki_3G » Sun Jan 17, 2021 2:55 pm

Yes Q will eventually reach K. And Q is expressed when equilibrium has not yet been reached.

Julianna_flores3E
Posts: 91
Joined: Wed Sep 30, 2020 9:52 pm

Re: q vs k

Postby Julianna_flores3E » Sun Jan 17, 2021 3:07 pm

Yes, Q will equal K at equilibrium, while K will not change values (unless the temp is changed) Q will.

josephspindler2H
Posts: 92
Joined: Wed Sep 30, 2020 9:54 pm
Been upvoted: 1 time

Re: q vs k

Postby josephspindler2H » Sun Jan 17, 2021 3:36 pm

Yeah Q will become K, Q is indeed the value when not at equilibrium. Q wants to become closer and closer to K in order to reach equilibrium.

Ethan Goode 2H
Posts: 129
Joined: Wed Sep 30, 2020 9:51 pm

Re: q vs k

Postby Ethan Goode 2H » Sun Jan 17, 2021 3:41 pm

Q is the quotient and will reach K at equilibrium. In the sapling problems there are a few examples of the relationship between q and k, and how knowing both those numbers will tell you which way the reaction is heading.

Daniela Santana 2L
Posts: 91
Joined: Wed Sep 30, 2020 9:59 pm

Re: q vs k

Postby Daniela Santana 2L » Sun Jan 17, 2021 7:54 pm

Hi! Yes you're right, the q value will eventually equal k, when it does this signifies that the reaction is at equilibrium. Yes Q can be calculated at any time, K is only when the reaction is at equilibrium.

RaniyaFeroz_1E
Posts: 90
Joined: Wed Sep 30, 2020 9:32 pm

Re: q vs k

Postby RaniyaFeroz_1E » Sun Jan 17, 2021 7:56 pm

Yes, Q can reach K, and when that occurs (Q=K) then the reaction is at equilibrium. Also, yes Q is the value that is calculated when the reaction isn't at equilibrium. On the other hand, K is only calculated when the reaction is at equilibrium.

RaniyaFeroz_1E
Posts: 90
Joined: Wed Sep 30, 2020 9:32 pm

Re: q vs k

Postby RaniyaFeroz_1E » Sun Jan 17, 2021 7:56 pm

Yes, Q can reach K, and when that occurs (Q=K) then the reaction is at equilibrium. Also, yes Q is the value that is calculated when the reaction isn't at equilibrium. On the other hand, K is only calculated when the reaction is at equilibrium.

Sarah Huh 1K
Posts: 41
Joined: Wed Nov 18, 2020 12:26 am

Re: q vs k

Postby Sarah Huh 1K » Sun Jan 17, 2021 9:02 pm

K is the equilibrium constant, while Q is the equilibrium at any given point.

Kyle_Lee_2B
Posts: 54
Joined: Wed Sep 30, 2020 9:42 pm

Re: q vs k

Postby Kyle_Lee_2B » Sun Jan 17, 2021 9:04 pm

You actually can use q to figure what side the reaction will go to. If q is greater than k the system will shift to the left and if q is less than k the system will shift right.

Bhuvan Kommineni 3L
Posts: 42
Joined: Thu Dec 17, 2020 12:18 am

Re: q vs k

Postby Bhuvan Kommineni 3L » Sun Jan 17, 2021 9:05 pm

Yes, the Q value will eventually reach K if the reaction is currently not at equilibrium. If it is at equilibrium then Q = K.

Bai Rong Lin 2K
Posts: 91
Joined: Wed Sep 30, 2020 9:54 pm

Re: q vs k

Postby Bai Rong Lin 2K » Sun Jan 17, 2021 9:55 pm

Q is when it is not in equilibrium, and it reaches k when in equilibrium.

Lauren Mungo 1K
Posts: 90
Joined: Wed Sep 30, 2020 10:08 pm
Been upvoted: 1 time

Re: q vs k

Postby Lauren Mungo 1K » Sun Jan 17, 2021 9:59 pm

Q is the concentrations at some point before equilibrium is reached and K is at equilibrium.

Carlos Martinez 2K
Posts: 15
Joined: Wed Nov 14, 2018 12:20 am

Re: q vs k

Postby Carlos Martinez 2K » Sun Jan 17, 2021 10:00 pm

yep, Q is just a point taken at a certain temperature. When Q=K then it is at equilibrium!

Mansi Solanki 3A
Posts: 91
Joined: Wed Sep 30, 2020 9:55 pm
Been upvoted: 1 time

Re: q vs k

Postby Mansi Solanki 3A » Sun Jan 17, 2021 10:03 pm

The Q value is the concentrations of the products over the concentration of the reactants at any point in time of the system. This means that Q could be equal to K if the concentrations are equal or proportional to the concentrations at K. Otherwise, Q being greater than or less than K can determine the direction of the system over time. This is all true at any one certain temperature and changes if the temperature is changed.

nayha a 1E
Posts: 96
Joined: Wed Sep 30, 2020 9:54 pm

Re: q vs k

Postby nayha a 1E » Sun Jan 17, 2021 10:04 pm

Q will equal K when the reaction reaches an equilibrium.

Giselle Granda 3F
Posts: 109
Joined: Wed Sep 30, 2020 10:00 pm

Re: q vs k

Postby Giselle Granda 3F » Sun Jan 17, 2021 10:07 pm

If Q does not equal K then the reaction is not at equilibrium. If it is less than K then the reaction will shift to the right towards the products to reach equilibrium. If it is greater than K, then it will shift to the left towards the reactants. This makes Q helpful in determining whether a reaction is at equilibrium or not.

Charmaine Ng 2D
Posts: 98
Joined: Wed Sep 30, 2020 9:37 pm

Re: q vs k

Postby Charmaine Ng 2D » Sun Jan 17, 2021 10:26 pm

Yes, the Q value is the ratio of product/reactant concentrations not at equilibrium, and yes, it should eventually reach equilibrium!

Kyla Villarama 1E
Posts: 90
Joined: Wed Nov 20, 2019 12:18 am

Re: q vs k

Postby Kyla Villarama 1E » Sun Jan 17, 2021 10:35 pm

When Q becomes the same as K, then it is at equilibrium.

Linette Choi 3L
Posts: 93
Joined: Wed Sep 30, 2020 9:51 pm

Re: q vs k

Postby Linette Choi 3L » Sun Jan 17, 2021 10:42 pm

If q and K are equal then the reaction is at equilibrium.

Jack_Pearce_2H
Posts: 99
Joined: Wed Sep 30, 2020 9:48 pm

Re: q vs k

Postby Jack_Pearce_2H » Sun Jan 17, 2021 10:43 pm

It will eventually reach K yes and q is the initial value measured before k is established

joshtully
Posts: 92
Joined: Wed Sep 30, 2020 9:36 pm

Re: q vs k

Postby joshtully » Sun Jan 17, 2021 10:44 pm

Q will equal K at equilibrium.

Sable Summerfield
Posts: 34
Joined: Tue Nov 17, 2020 12:18 am

Re: q vs k

Postby Sable Summerfield » Sun Jan 17, 2021 10:47 pm

Is there a less obvious explanation for how Q>K because K decreased and K increased because Q< K? The relationship between Q and K is kind of confusing when getting into why Q is < K when the Reactants transfer to the Products side.

Aria Movassaghi 1A
Posts: 97
Joined: Wed Sep 30, 2020 9:40 pm

Re: q vs k

Postby Aria Movassaghi 1A » Sun Jan 17, 2021 10:48 pm

when q=k, it is at equilibrium

Arnav Saud 2C
Posts: 117
Joined: Wed Sep 30, 2020 9:51 pm

Re: q vs k

Postby Arnav Saud 2C » Sun Jan 17, 2021 10:59 pm

When q=k, the reaction is at equilibrium.
If q is greater that k, it means that the reaction will produce more reactants.
If q is less than k, it means that the reaction will produce more products.

Ethan Laureano 3H
Posts: 92
Joined: Wed Sep 30, 2020 9:58 pm

Re: q vs k

Postby Ethan Laureano 3H » Sun Jan 17, 2021 11:14 pm

Q is the products over reactants at any time of the reaction. If Q=K, then the reaction is at equilibrium. If not, you can determine where the reaction will go to (the products side or the reactants side).

Hasan Mirza 3F
Posts: 90
Joined: Wed Sep 30, 2020 10:00 pm

Re: q vs k

Postby Hasan Mirza 3F » Sun Jan 17, 2021 11:16 pm

Q moves towards K and when they equal the same thing, the reaction is at equilibrium.

rhettfarmer-3H
Posts: 101
Joined: Wed Sep 30, 2020 9:59 pm

Re: q vs k

Postby rhettfarmer-3H » Sun Jan 17, 2021 11:18 pm

Yeah, q will eventually become K. Q is the product and reaction ratio at a certain time of the reaction. However, as we can infer that it takes a while to get to K. so q is the intermediate until we reach it. Therefore, Q is just a notion of a certain time before it hits K.

Caelin Brenninkmeijer 1G
Posts: 90
Joined: Wed Sep 30, 2020 9:50 pm

Re: q vs k

Postby Caelin Brenninkmeijer 1G » Sun Jan 17, 2021 11:20 pm

The Q value will always come back to equal K. Once the two values are equivalent, it means that the reaction is at equilibrium.


Return to “Non-Equilibrium Conditions & The Reaction Quotient”

Who is online

Users browsing this forum: No registered users and 1 guest