q vs k

[connie 2C]

will the q value eventually reach k? is q the value that is calculated when the reaction is not at equilibrium?

[Naneeta Desar 1K]

Yes Q is the value calculated when the reaction is not at equilibrium.

[VLi_2B]

Q is the reaction quotient and expresses the relative ratio of products to reactants at a given instant. On the other hand, K is the equilibrium constant and is used to calculate the final concentrations at equilibrium for a reaction using an ICE table. If Q and K equal each other, the reaction is at equilibrium.

[Ian Morris 3C]

When Q reaches K, it is at equilibrium.

[Mitchell Koss 4G]

Yes if a reaction reaches equilibrium, it will have Q=K

[Christineg1G]

Yes, when Q=K the solution has reached its equilibrium composition and doesn't change in either direction.

[Lauren Tanaka 1A]

Yes Q is just the value of equilibrium at any given point and K is the equilibrium constant. When Q and K are equal, that would show you that the reaction is at equilibrium.

[505306205]

Q value is calculated when you don't know whether the reaction is at equilibrium or not. If Q equals K, then the reaction is at equilibrium.

[Joowon Seo 3A]

The q value will eventually reach k given a long period of time, because that's where the reaction occurs at equilibrium.

[aishwarya_atmakuri]

Q represents the current state of the system but K is the equilibrium state. Eventually, Q will go towards K.

[Asia Yamada 2B]

Yes, Q is the reaction quotient that is calculated at any point in time during the reaction. You can compare Q to K to determine which way the reaction will proceed to eventually establish equilibrium where Q=K.

[reyvalui_3g]

Q is the reaction quotient for any specific moment during a reaction, technically Q does not approach K but the concentrations of the reactant and products will change so that the ratio will be equal to K.

[alebenavides]

basically once Q reaches K it reaches the equilibrium needed.

[Becca Nelson 3F]

Q should reach K if the reaction is left alone. Once Q equals K the reaction is at equilibrium and the forward and reverse rates of the reaction are the same. If Q > K more reactants will be formed and if Q<K more products will be formed until these values are the same.

[Aayushi Jani 3A]

Q is the reaction quotient (taken at any time during the reaction). If you let the reaction go until it reaches equilibrium, Q should equal K (since K is the equilibrium constant).

[Morgan Gee 3B]

Q is the reaction quotient which is the concentration of products to the concentration of reactants raised to their coefficients. Q can be less than K, greater than K, and equal to K. When Q is less than K, that means there are more reactants than products and the forward reaction needs to occur at a greater rate to reach equilibrium. When Q is greater than K, that means there are more products than reactants and the reverse reaction needs to occur at a greater rate to reach equilibrium. When Q equals K, the reaction is at equilibrium.

[Ava Nickman]

yes k and q are the same but k represents the ratio at equilibrium and and q represents other points in the reaction

[VincentLe_3A]

Yes, q will eventually reach k after letting the reaction take place over time. Q is finding the ratio at a certain time during the reaction, which could be greater than, less than, or equal to k. If the q is equal to k, then the reaction is at equilibrium. However, if q<k, that means there are more reactants in the ratio compared to the equilibrium constant ratio, so the reaction will form more products so that the equilibrium constant is reached. Same applies when q>k, which means there are more products in the ratio, so the reaction will form more reactants so that the equilibrium constant is attained.

[Lorraine Jiang 2C]

Hi! The reaction quotient basically represents the concentration of production to reactant at any given time in the reaction. However, K specifically implies the ratio at equilibrium.

Hope it helps!

[Lauren To 1E]

Yes, Q=K once the reaction is at equilibrium. We use Q for calculations when we're unsure if the reaction has reached equilibrium.

[Jason Knight - 1F]

Q, the reaction quotient, tells us the [p]/[r] ratio at any point in the reaction. The value of Q then tells us if our reaction is at equilibrium if (Q=K). If K>Q, then the forward reaction is favored, and if K<Q, then the reverse reaction is favored. We use Q when we are not sure if the reaction is at equilibrium or not.

[Ivy Tan 1E]

Hi!
Q is the reaction quotient, or the ratio of products to reactants at any given point in the reaction. Q may equal K (when the reaction is at equilibrium) or it may higher or lower than K (when the reaction is not at equilibrium). If Q is higher than K, the reaction favors the reactants. If Q is lower than K, the reaction favors the products. Hope this helps!!

[Melis Kasaba 2B]

Q is the reaction quotient and can be used to figure out which direction the reaction will shift in order to reach equilibrium.

K > Q: reaction proceeds forward, R --> P.
K < Q: reaction proceeds in reverse direction, P --> R.
Q = K: system is at equilibrium, no shift to either left or right

[Rob Tsai 2F]

I don't know if this right, but I like to think of Q as any random moment in time during my life, and K as my home. I could be out and about at school, hitting the town on a Saturday night, or watching TV on my couch (pre/post quarantine of course). Q can either be greater than, less than, or equal to K. It all depends on what "moment" you choose (what concentrations/partial pressures) you are given. Sorry if that didn't make sense, I'm feeling kind of poetic today.

[Nina Fukui 2J]

they're both the same calculation method but the letter q usually means the solution isn't at equilibrium. but eventually q should reach k after a certain period of time

[Navdha Sharma 3J]

Q and K are calculated in the same way but Q is the calculation that is not done at equilibrium.

[Mingzi Yang 1E]

If Q equals K, the reaction is at equilibrium. Q is calculated the same way as K when the reaction is not at equilibrium.

[Karen Elrayes 1L]

Q calculates the ratio of products to reactants at anyone point not just equilibrium.

[David Jen 1J]

Q calculates the same way as K, but Q calculates at concentrations that aren't equilibrium.

[Gicelle Rubin 1E]

Q is the reaction quotient and can be used to figure out which direction the reaction will shift in order to reach equilibrium.

K > Q: reaction proceeds forward, R --> P.
K < Q: reaction proceeds in reverse direction, P --> R.
Q = K: system is at equilibrium, no shift to either left or right

Thank you for making it easy to understand :)

[Will Skinner]

Yes q will eventually reach k if the temperature remains the same. Also I think of q as a ratio that changes as the reaction continues and becomes equal to k when the reaction “finishes”.

[Uyen Trinh 3C]

At equilibrium, Q=K. When the value of Q is not the same as the value of K_c, the reaction is not at equilibrium.

Additionally, when Q is less than K_c, the reaction will shift to form more products to reach equilibrium. Vice versa, when Q is more than K_c, the reaction will shift to form more reactants to reach equilibrium.

So eventually if you wait long enough Q=K.

[OmarArafat_2K]

Yes, it will eventually. Q is the current state reaction quotient and K is the equilibrium constant. Q will eventually reach equilibirum.

[Chinmayi Mutyala 3H]

If Q = K, the reaction is at equilibrium.

[Shivani Kapur 2J]

When Q = K, the reaction is at equilibrium. K will only change with a temperature change, but Q will change depending on factors such as changes in concentration and pressure.

[Rose_Malki_3G]

Yes Q will eventually reach K. And Q is expressed when equilibrium has not yet been reached.

[Julianna_flores3E]

Yes, Q will equal K at equilibrium, while K will not change values (unless the temp is changed) Q will.

[josephspindler2H]

Yeah Q will become K, Q is indeed the value when not at equilibrium. Q wants to become closer and closer to K in order to reach equilibrium.

[Ethan Goode 2H]

Q is the quotient and will reach K at equilibrium. In the sapling problems there are a few examples of the relationship between q and k, and how knowing both those numbers will tell you which way the reaction is heading.

[Daniela Santana 2L]

Hi! Yes you're right, the q value will eventually equal k, when it does this signifies that the reaction is at equilibrium. Yes Q can be calculated at any time, K is only when the reaction is at equilibrium.

[RaniyaFeroz_1E]

Yes, Q can reach K, and when that occurs (Q=K) then the reaction is at equilibrium. Also, yes Q is the value that is calculated when the reaction isn't at equilibrium. On the other hand, K is only calculated when the reaction is at equilibrium.

[RaniyaFeroz_1E]

Yes, Q can reach K, and when that occurs (Q=K) then the reaction is at equilibrium. Also, yes Q is the value that is calculated when the reaction isn't at equilibrium. On the other hand, K is only calculated when the reaction is at equilibrium.

[Sarah Huh 1K]

K is the equilibrium constant, while Q is the equilibrium at any given point.

[Kyle_Lee_2B]

You actually can use q to figure what side the reaction will go to. If q is greater than k the system will shift to the left and if q is less than k the system will shift right.

[Bhuvan Kommineni 3L]

Yes, the Q value will eventually reach K if the reaction is currently not at equilibrium. If it is at equilibrium then Q = K.

[Bai Rong Lin 2K]

Q is when it is not in equilibrium, and it reaches k when in equilibrium.

[Lauren Mungo 1K]

Q is the concentrations at some point before equilibrium is reached and K is at equilibrium.

[Carlos Martinez 2K]

yep, Q is just a point taken at a certain temperature. When Q=K then it is at equilibrium!

[Mansi Solanki 3A]

The Q value is the concentrations of the products over the concentration of the reactants at any point in time of the system. This means that Q could be equal to K if the concentrations are equal or proportional to the concentrations at K. Otherwise, Q being greater than or less than K can determine the direction of the system over time. This is all true at any one certain temperature and changes if the temperature is changed.

[nayha a 1E]

Q will equal K when the reaction reaches an equilibrium.

[Giselle Granda 3F]

If Q does not equal K then the reaction is not at equilibrium. If it is less than K then the reaction will shift to the right towards the products to reach equilibrium. If it is greater than K, then it will shift to the left towards the reactants. This makes Q helpful in determining whether a reaction is at equilibrium or not.

[Charmaine Ng 2D]

Yes, the Q value is the ratio of product/reactant concentrations not at equilibrium, and yes, it should eventually reach equilibrium!

[Kyla Villarama 1E]

When Q becomes the same as K, then it is at equilibrium.

[Linette Choi 3L]

If q and K are equal then the reaction is at equilibrium.

[Jack_Pearce_2H]

It will eventually reach K yes and q is the initial value measured before k is established

[joshtully]

Q will equal K at equilibrium.

[Sable Summerfield]

Is there a less obvious explanation for how Q>K because K decreased and K increased because Q< K? The relationship between Q and K is kind of confusing when getting into why Q is < K when the Reactants transfer to the Products side.

[Aria Movassaghi 1A]

when q=k, it is at equilibrium

[Arnav Saud 2C]

When q=k, the reaction is at equilibrium.
If q is greater that k, it means that the reaction will produce more reactants.
If q is less than k, it means that the reaction will produce more products.

[Ethan Laureano 3H]

Q is the products over reactants at any time of the reaction. If Q=K, then the reaction is at equilibrium. If not, you can determine where the reaction will go to (the products side or the reactants side).

[Hasan Mirza 3F]

Q moves towards K and when they equal the same thing, the reaction is at equilibrium.

[rhettfarmer-3H]

Yeah, q will eventually become K. Q is the product and reaction ratio at a certain time of the reaction. However, as we can infer that it takes a while to get to K. so q is the intermediate until we reach it. Therefore, Q is just a notion of a certain time before it hits K.

[Caelin Brenninkmeijer 1G]

The Q value will always come back to equal K. Once the two values are equivalent, it means that the reaction is at equilibrium.