Value of X

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Andrea_Torres
Posts: 98
Joined: Sun Sep 15, 2019 12:15 am

Value of X

Postby Andrea_Torres » Thu Jan 23, 2020 6:32 pm

How do we find the value of x when it is not given?

Subashni Rajiv 1K
Posts: 101
Joined: Wed Sep 18, 2019 12:16 am

Re: Value of X

Postby Subashni Rajiv 1K » Thu Jan 23, 2020 7:09 pm

You would use the Ka or Kb value and use an ice table to solve for x. If you're given the final concentration of any of the products you can work backwards, since the change in product concentration is equal to the final concentration.

Ryan Yee 1J
Posts: 101
Joined: Sat Aug 17, 2019 12:16 am

Re: Value of X

Postby Ryan Yee 1J » Thu Jan 23, 2020 7:28 pm

You have to solve for the value of x most of the time, using K values (including Ka or Kb) set equal to the equilibrium expression. From there you can add x to the products and subtract it from reactants to find final concentrations.

RRahimtoola1I
Posts: 102
Joined: Fri Aug 09, 2019 12:15 am

Re: Value of X

Postby RRahimtoola1I » Sat Jan 25, 2020 12:07 pm

Set up a K expression using an ICE table and solve for x setting the expression equal to Ka, Kb, or Kc.

Sukanya Mohapatra 2G
Posts: 100
Joined: Sat Aug 17, 2019 12:18 am
Been upvoted: 1 time

Re: Value of X

Postby Sukanya Mohapatra 2G » Sat Jan 25, 2020 4:39 pm

You would need to use an ICE table and then equate to K to solve for X.

Jasmine Vallarta 2L
Posts: 102
Joined: Sat Aug 17, 2019 12:18 am

Re: Value of X

Postby Jasmine Vallarta 2L » Sat Jan 25, 2020 4:57 pm

you use the K value and equate it to the ice table values, then solve for x with algebra

Michelle N - 2C
Posts: 117
Joined: Wed Sep 18, 2019 12:19 am

Re: Value of X

Postby Michelle N - 2C » Sat Jan 25, 2020 9:09 pm

Really depends on what's given, but it's generally through an ICE table with the quadratic formula.

Maria Poblete 2C
Posts: 102
Joined: Wed Sep 18, 2019 12:15 am

Re: Value of X

Postby Maria Poblete 2C » Sun Jan 26, 2020 12:32 pm

What everyone else said above is correct. Something to keep in mind is that if you are calculating for a weak acid/base, the change in molarity at equilibrium can be considered negligible because they do not 100% dissociate in solution. So, even though you have a change in X, the change is still close to 0 and can be considered 0.


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