Endothermic/exothermic reactions and K
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Endothermic/exothermic reactions and K
For endothermic reactions, how does K change when you add heat. How does K change when you add heat to exothermic reactions? Also, why does K change instead of Q when you add heat to the reaction.
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Re: Endothermic/exothermic reactions and K
K changes because temperature changes the equilibrium constant itself. For an endothermic reaction, which means a positive delta H, K becomes bigger because the production of products is favored so the numerator of the K ratio is bigger when heated.On the other hand, for an exothermic reaction where delta H is negative, K becomes smaller because heating it will favor reactant production. By cooling it, products are favored thus K becomes bigger.
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Re: Endothermic/exothermic reactions and K
Hi! For exothermic reactions, heat is released for the forward reaction; thus, the addition of heat would favor the reverse reaction instead to produce more reactants, and the K value would decrease. For endothermic reactions, heat is absorbed for the forward reaction; thus, the addition of heat would favor the forward reaction to produce more products, and the K value would increase. Hope this helps!
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Re: Endothermic/exothermic reactions and K
When there is an endothermic reaction, you can think of heat as a reactant. Increasing the temperature makes K increase because the equilibrium favors more products and less reactants. We know that K=[P]/[R], so if your denominator is smaller then the value of K will be bigger. In an exothermic reaction, you can think of heat as a product. Increasing the temperature makes K decrease because the equilibrium favors more reactants and less products. This means that in your equilibrium constant (K=[P]/[R]) the denominator will be bigger and therefore make K decrease.
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Re: Endothermic/exothermic reactions and K
I like to think about it as what each reaction "wants":
Endothermic reactions "want" heat so an increase in temperature favors the forward reaction and increases the value of K (and vice versa).
Exothermic reactions do not "want" heat, so an increase in temperature favors the reverse reaction and decreases the value of K (and vice versa).
Endothermic reactions "want" heat so an increase in temperature favors the forward reaction and increases the value of K (and vice versa).
Exothermic reactions do not "want" heat, so an increase in temperature favors the reverse reaction and decreases the value of K (and vice versa).
Re: Endothermic/exothermic reactions and K
Hey!
So exothermic reactions release heat when turning into products, so when you add more heat to the system, products will tend to form reactants more often, the equilibrium will shift to favor the reactants more. Since K is equivalent to the products raised to their stoichiometric coefficients, over the reactants to their stoichiometric coefficients, K will decrease as the reaction shifts to the reactants. The inverse is true of endothermic reactions. Heat is taken up when forming products, so adding heat will favor the products, causing K to increase. And K changes because the actual ratio of products and reactants changes when temperature changes, whereas Q just describes the state of the system, so if k changes, Q will also start to change to reach equilibrium again.
So exothermic reactions release heat when turning into products, so when you add more heat to the system, products will tend to form reactants more often, the equilibrium will shift to favor the reactants more. Since K is equivalent to the products raised to their stoichiometric coefficients, over the reactants to their stoichiometric coefficients, K will decrease as the reaction shifts to the reactants. The inverse is true of endothermic reactions. Heat is taken up when forming products, so adding heat will favor the products, causing K to increase. And K changes because the actual ratio of products and reactants changes when temperature changes, whereas Q just describes the state of the system, so if k changes, Q will also start to change to reach equilibrium again.
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Re: Endothermic/exothermic reactions and K
Hi! So K will change because the change in temperature has an affect on the equilibrium constant. If the delta H is positive (endothermic reaction) and heat is added, it will cause K to increase because it will favor products being made since an increase in heat will favor the forward reaction. If delta H is negative (exothermic) and heat is added, it will favor the reactants and K will decrease
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Re: Endothermic/exothermic reactions and K
For endothermic reactions, K increases when temperature increases
For exothermic reactions, K decreases when temperature increases.
For exothermic reactions, K decreases when temperature increases.
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Re: Endothermic/exothermic reactions and K
Hi! K changes when you add heat to a reaction because the equilibrium constant changes. More reactants will be produced, so reactants would be favored. K will increase as the temperature increases in endothermic reactions, and it will decrease when temperature increases in an exothermic reaction.
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Re: Endothermic/exothermic reactions and K
A change in temperature changes the equilibrium constant K. When increasing the heat and the reaction is endothermic, K will increase. When increasing the heat and the reaction is exothermic, K will decrease.
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Re: Endothermic/exothermic reactions and K
If a reaction is endothermic and temperature is increased, K will increase. If the reaction is exothermic and temperature is increased, then K will decrease.
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