Deprotonation Percentage Formula

Moderators: Chem_Mod, Chem_Admin

Sabrina Galvan 3J
Posts: 91
Joined: Wed Sep 30, 2020 9:35 pm
Been upvoted: 1 time

Deprotonation Percentage Formula

Postby Sabrina Galvan 3J » Sat Jan 23, 2021 10:22 pm

What is the formula for finding the percentage of deprotonation?

ChihWei Chen 2C
Posts: 46
Joined: Wed Nov 18, 2020 12:24 am

Re: Deprotonation Percentage Formula

Postby ChihWei Chen 2C » Sat Jan 23, 2021 10:26 pm

I believe it's (the equilibrium concentration of product / the initial concentration of the molecule asked by the question) times 100%.

Hannah Biju 1E
Posts: 94
Joined: Wed Sep 30, 2020 9:55 pm

Re: Deprotonation Percentage Formula

Postby Hannah Biju 1E » Sat Jan 23, 2021 10:27 pm

x/initial concecntration * (100%)

x is the value that you solved for using the quadratic formula.

Brianna Chen 3F
Posts: 98
Joined: Wed Sep 30, 2020 10:11 pm

Re: Deprotonation Percentage Formula

Postby Brianna Chen 3F » Sat Jan 23, 2021 10:51 pm

It is the same as the percentage protonation formula but for acids which is [concentration of A- after equilibrium]/[initial concentration of HA] x 100%.

Nishka Vipul 1J
Posts: 48
Joined: Thu Dec 17, 2020 12:18 am

Re: Deprotonation Percentage Formula

Postby Nishka Vipul 1J » Sat Jan 23, 2021 11:05 pm

The formula is (equilibrium concentration/initial concentration of HA)*100! The equilibrium concentration is usually what we are solving for when using the quadratic formula (as someone mentioned above).
Hope this helped!

Michael Cardenas 3B
Posts: 56
Joined: Wed Sep 30, 2020 9:34 pm

Re: Deprotonation Percentage Formula

Postby Michael Cardenas 3B » Sun Jan 24, 2021 12:38 am

The formula is equilibrium concentration(found using the quadratic formula and ice table)/ initial concentration of HA *100%.

Gustavo_Chavez_1K
Posts: 92
Joined: Wed Sep 30, 2020 9:46 pm

Re: Deprotonation Percentage Formula

Postby Gustavo_Chavez_1K » Sun Jan 24, 2021 5:53 pm

The formula is the (equilibrium constant/initial concentration of HA) x 100%


Return to “Non-Equilibrium Conditions & The Reaction Quotient”

Who is online

Users browsing this forum: No registered users and 2 guests