Achieve #5: Week 2  [ENDORSED]

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005801694
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Achieve #5: Week 2

Postby 005801694 » Sun Jan 16, 2022 11:15 pm

Hi! When calculating the % protonated, why do you calculate the formal concentration of B (the base) by adding the concentration of B and BH+ together? I'm referring to the reaction: B+H20->(BH+)+OH-. Thanks!

Joanna Zhao 1J
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Re: Achieve #5: Week 2

Postby Joanna Zhao 1J » Mon Jan 17, 2022 11:23 am

When calculating the % protonated, we need to find the amount dissociated and divide it by the INITIAL concentration of B before it began dissociating. Since [B]equilibrium = [B]initial - x, and [BH+]equilibrium = x, I guess you can say to find the initial [B] you need to add the two together because [B]initial is [B]equilibrium plus whatever got dissociated. It's like putting the puzzle pieces back together.

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Re: Achieve #5: Week 2  [ENDORSED]

Postby Chem_Mod » Mon Jan 17, 2022 11:24 am

The initial concentration of base can be calculated by adding the equilibrium concentrations of B and BH+ together.

The initial concentration of base is then used to calculate % protonated:

% protonated = [BH+]/[B]initial x 100


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