6D.15 part b

[SarahOMalley1D]

Hi! On 6D.15 part b, what would the reaction of AlCl3 with water look like? I know that chlorine would not be involved in the reaction. I also know that according to a table in the textbook, there is a Ka value for Al(H2O)6 3+. However, how would the reaction of this with water look like? I think one water molecule would lose one hydrogen, resulting in Al(H2O)5(OH)2+ and H3O+, but I'm not completely sure about this.

[AlexandriaHunt2J]

Hi! When Al3+ reacts with water, it acts as a Lewis acid. The equation of this reaction is as follows:

[Al(H2O)6]3+ (aq) + H2O (l) --> [Al(H2O)5(OH)]2+ (aq) + H3O+ (aq)

[Erin Woolmore 1C]

Where were you able to find the Ka value? I can't seem to find it in the tables they hyperlinked in the textbook.