Re: Ionization versus protonation
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Re: Ionization versus protonation
How do I know the difference between ionization and protonation when calculating equilibrium equation. How are the equation set-ups different from each other?
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Chem_Mod
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Re: Ionization versus protonation
Problems generally refer to % ionization or % dissociation or % protonation or % deprotonation.
% ionization = refers to the fraction of the original neutral species that has been ionized (has a charge). E.g., [CH3COO-]/[CH3COOH] x 100
You can also the term % dissociation here as an acid or base dissociating into its conjugate acid/base is the same thing as it becoming ionized.
Depending on whether you are dealing with an acid (Bronsted acid, loses protons) or a base (Bronsted base, acquires protons), you use the the terms % DEprotonation (for acid) and % PROtonation (for base) respectively.
Essentially, % ionization can refer to both % protonation and % deprotonation depending on the context of the problem.
Hope that helps!
% ionization = refers to the fraction of the original neutral species that has been ionized (has a charge). E.g., [CH3COO-]/[CH3COOH] x 100
You can also the term % dissociation here as an acid or base dissociating into its conjugate acid/base is the same thing as it becoming ionized.
Depending on whether you are dealing with an acid (Bronsted acid, loses protons) or a base (Bronsted base, acquires protons), you use the the terms % DEprotonation (for acid) and % PROtonation (for base) respectively.
Essentially, % ionization can refer to both % protonation and % deprotonation depending on the context of the problem.
Hope that helps!
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kayla fullerton 3A
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Re: Ionization versus protonation
Ionization is a broader term that includes protonation. For example, ionization can mean adding or taking away an electron, versus protonation is only losing electrons (or gaining protons). To figure out what the term represents specifically, you have to look at it in the context of the problem :)
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Anna_Aldridge_2C
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Re: Ionization versus protonation
Hi!
Ionization is the adding or taking away of an electron while protonation is only the adding of an electron. The other term you're looking for is deprotonation, which will be calculated differently than protonation because a proton will be removed. For protonation, the proton will be added to the base; the percent protonation can be found by dividing the concentration of the protonated molecules by the original concentration of the molecule (the base):
[HB+]/[Binitial] x 100 = % Protonated
For percent deprotonation, it will be the ratio of the deprotonated molecules over the original amount, but with the acid instead of base because the acid is a proton donator. Multiply by 100 for the percentage:
[A-]/[HAinitial] x 100 = % Deprotonated
Hope this helps!
Ionization is the adding or taking away of an electron while protonation is only the adding of an electron. The other term you're looking for is deprotonation, which will be calculated differently than protonation because a proton will be removed. For protonation, the proton will be added to the base; the percent protonation can be found by dividing the concentration of the protonated molecules by the original concentration of the molecule (the base):
[HB+]/[Binitial] x 100 = % Protonated
For percent deprotonation, it will be the ratio of the deprotonated molecules over the original amount, but with the acid instead of base because the acid is a proton donator. Multiply by 100 for the percentage:
[A-]/[HAinitial] x 100 = % Deprotonated
Hope this helps!
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