Fall 2012 Final #6B

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Christian Gequillo 1D
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Joined: Wed Sep 21, 2016 3:00 pm

Fall 2012 Final #6B

Postby Christian Gequillo 1D » Fri Dec 02, 2016 10:57 pm

In this question, why did we find the Molarity at the end of the solution rather than in the first few steps? In the answer, it shows that 0.045=(x/0.05-x) is divided by the volume (1.072). I thought molarity is required for the Kc equation. Or does it not matter?

Joshua Baysa 1J
Posts: 10
Joined: Wed Sep 21, 2016 2:59 pm

Re: Fall 2012 Final #6B

Postby Joshua Baysa 1J » Fri Dec 02, 2016 11:44 pm

You couldn't find the Molarity in the first few steps because the moles that it gives you (0.05) is the initial amount for PCl5. When they do (x^2)/(0.05-x) and divide that by the volume, it is the same thing as using the molarities of each since they equal mol/L

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