11.89 part a

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Christina Cen 2J
Posts: 53
Joined: Sat Jul 22, 2017 3:01 am

11.89 part a

Postby Christina Cen 2J » Tue Nov 28, 2017 9:04 pm

Could someone explain to me how to find the balanced chemical equation for this problem? I understand how to do part b based on the graph and the answer for part a, but I am unsure of how to find the coefficients for the equation.

Sean Monji 2B
Posts: 66
Joined: Fri Sep 29, 2017 7:06 am

Re: 11.89 part a

Postby Sean Monji 2B » Wed Nov 29, 2017 2:36 pm

You have the least of B, so it probably has the smallest coefficient and is a good place to start. It has a value of 5.
B = 5.
From there, C has twice as much product created than B, so the ratio from B to C is 1:2. Therefore, C's coefficient must be twice as much as B's. (as you can see it is 10).
C = 10.
Since A is a reactant, you must look at the amount of A is consumed (final minus initial) as we don't care how much A we have in excess but rather how much A is reacted in the chemical reaction. A starts at roughly 27.5 and goes to 17.5. That means 10 reactant was used to create the products.
A = 10.

10A = 5B + 10C
Simplify
2A = B + 2C

Hope that helps


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