Concept Q// Change in Temp
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Concept Q// Change in Temp
How does heating favor the formation of reactants when the reaction is exothermic while forming product?
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- Posts: 52
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Re: Concept Q// Change in Temp
If a reaction is exothermic and the temperature is increased, the reaction will shift to the left in order to reduce the temperature. When the reactants are favored, more heat is absorbed (Which helps absorbed the extra heat and reach equilibrium again).
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Re: Concept Q// Change in Temp
When I do these problems, I like to think of heat as one of the reactants or products. For an endothermic reaction, I think of the energy as a reactant because the reaction requires energy, and when a reaction is exothermic, I think of the energy as a product because it releases energy. With this in mind, the reaction will shift just like it would if you were adding/removing reactants/products.
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Re: Concept Q// Change in Temp
I really like this concept ^. But if that somehow doesn't help, it might help to think of it this way. Endothermic means for a reaction to require heat, which means that if heat is increased, more reactants will be able to turn into products. However, Professor says for the opposite is true. If the reaction is exothermic, then the reverse reaction is favored; the products more readily reverse react into reactants. Lavelle liked to think of it in terms of opposites, or at least that's what i caught on to.
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