Question 11.89 Part A
Moderators: Chem_Mod, Chem_Admin
-
- Posts: 60
- Joined: Thu Jul 13, 2017 3:00 am
- Been upvoted: 1 time
Question 11.89 Part A
Why does the answer state that 2A forms B + C. Where did they get 2A from the graph?
-
- Posts: 51
- Joined: Thu Jul 27, 2017 3:01 am
- Been upvoted: 2 times
Re: Question 11.89 Part A
It could possibly be that they are trying to balance the coefficients on each side, so if A is a reactant, and B and C are the products, then there needs to be two (lets say) moles on the reactant and product side of the equation.
-
- Posts: 55
- Joined: Thu Jul 13, 2017 3:00 am
Re: Question 11.89 Part A
In my solutions book it said 2A forms B + 2C. When I got this answer, it was because of the way I did my ice box. If A starts at ~27 and B and C start at 0, you look at their final partial pressures to find the change
A B C
i 27 0 0
c -x
e 17 5 10
so if you calculate -x to be 10, then the change in B, which is 5 is 0.5x, and the change in C is x. If you assume that there is one mole of A, that gives you
A <-> 0.5B + C. Since you can't have fractions in balanced equations, the resultant equation would be 2A <-> B + 2C
A B C
i 27 0 0
c -x
e 17 5 10
so if you calculate -x to be 10, then the change in B, which is 5 is 0.5x, and the change in C is x. If you assume that there is one mole of A, that gives you
A <-> 0.5B + C. Since you can't have fractions in balanced equations, the resultant equation would be 2A <-> B + 2C
Return to “Applying Le Chatelier's Principle to Changes in Chemical & Physical Conditions”
Who is online
Users browsing this forum: SainehaMaddineni_3I, Simer_Shera_2D and 1 guest