## Question 11.89 Part A

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### Question 11.89 Part A

Why does the answer state that 2A forms B + C. Where did they get 2A from the graph?

Chris Pleman 3E
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### Re: Question 11.89 Part A

It could possibly be that they are trying to balance the coefficients on each side, so if A is a reactant, and B and C are the products, then there needs to be two (lets say) moles on the reactant and product side of the equation.

Pooja Nair 1C
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Joined: Thu Jul 13, 2017 3:00 am

### Re: Question 11.89 Part A

In my solutions book it said 2A forms B + 2C. When I got this answer, it was because of the way I did my ice box. If A starts at ~27 and B and C start at 0, you look at their final partial pressures to find the change
A B C
i 27 0 0
c -x
e 17 5 10

so if you calculate -x to be 10, then the change in B, which is 5 is 0.5x, and the change in C is x. If you assume that there is one mole of A, that gives you
A <-> 0.5B + C. Since you can't have fractions in balanced equations, the resultant equation would be 2A <-> B + 2C

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