In the example,
B(g) + C(g)<-->A(s)
If volume is decreased, would I say the reaction favors products because mole ratio is (2:0)?
Mole Ratio with a Solid [ENDORSED]
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Matthew Tran 1H
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Re: Mole Ratio with a Solid [ENDORSED]
You are correct. Using the quick method, solids don't exert pressure, so decreasing the volume (and therefore increasing the pressure/concentrations of reactants) would cause the reaction to favor the formation of products by Le Chatelier's principle.
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amogha_koka3I
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Xinyi Zeng 4C
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Re: Mole Ratio with a Solid
amogha_koka3I wrote:Is it the same case for liquids as it is for solids?
Yes, it should be the same case in this example, as liquid don't contribute much towards pressure like solids.
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