Change in Pressure
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Re: Change in Pressure
You want to think of change in pressure as a change in volume. This will affect the reaction by changing concentrations and pushing the system away from equilibrium. Therefore, with the new concentration values, you will be solving for Q rather than K. By comparing the two you can determine which way the reaction will shift to return to equilibrium.
Hope this helps!
Hope this helps!
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Re: Change in Pressure
Increasing the pressure on a reaction involving reacting gases increases the rate of reaction. Changing the pressure on a reaction that involves only solids or liquids has no effect on the rate.
If you increase the pressure of a gas, you squeeze it into a smaller volume.
In order for any reaction to happen, the particles must first collide. If there are more molecules in a smaller volume, the chances of collision are greater, and the rate increases.
If you increase the pressure of a gas, you squeeze it into a smaller volume.
In order for any reaction to happen, the particles must first collide. If there are more molecules in a smaller volume, the chances of collision are greater, and the rate increases.
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Re: Change in Pressure
In response to a change in pressure (due to decreased volume), a reaction will either shift to the right or the left to maintain equilibrium. A quick way to predict how a reaction will react is: if there are more moles on the right, the reaction will shift to the left and if there are more moles on the left side of the reaction, the reaction will shift to the right.
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Re: Change in Pressure
When decreasing the volume of the container, the reaction will favor the side which produces less moles. This is due to the fact that reducing volume increases concentration (moles/volume=conc), so, following Le Chatlier's Principle, the reaction will try to minimize changes in concentration.
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