Change in Pressure, 5J.5

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Daisylookinland
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Joined: Fri Sep 28, 2018 12:28 am

Change in Pressure, 5J.5

Postby Daisylookinland » Wed Jan 16, 2019 10:31 pm

Can anyone explain the reasoning behind the textbook problem 5J. 5 (7th edition)? I understand why in part d there would be no change, but for a,b,c, and e I'm confused as to how you would know reactants would be favored with an overall increase in pressure.

Camille Marangi 2E
Posts: 60
Joined: Fri Sep 28, 2018 12:26 am

Re: Change in Pressure, 5J.5

Postby Camille Marangi 2E » Thu Jan 17, 2019 1:47 pm

Reactants just so happened to be favored in all of these because the reactants side had less stoichiometric moles than the products side did in each scenario. For example in part a, the reactants has 2 stoichiometric moles of O3 while the products has 3 stoichiometric moles of O2- therefore when the reaction is compressed, the reactants side is favored simply because it has the lesser amount of moles. For b, we cannot include the solid carbon-due to it being solid- and thus we have 1 mole of reactant vs. 2 moles of product and again we see the reactants are favored. This concept can be used for the rest of the problems as well


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