Lecture 1/18/19

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SydBenedict2H
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Joined: Wed Nov 08, 2017 3:00 am

Lecture 1/18/19

Postby SydBenedict2H » Sun Jan 20, 2019 10:40 pm

Can someone explain the last example he did on Friday? Im a little confused still as to how/why NO2- was 0.15 and H3O+ was still 0

Arianna Ko 2E
Posts: 33
Joined: Fri Sep 28, 2018 12:20 am

Re: Lecture 1/18/19

Postby Arianna Ko 2E » Sun Jan 20, 2019 10:53 pm

You know that you started off with 0.150M of NO2- given that you had 0.150M of KNO2. The initial concentration then of NO2- will be 0.150M. Because initially there is no reaction occurring, there are no H3O+ molecules yet that formed from the deprotonation of HNO2. So, you start with 0 for H3o+ and 0.150 for NO2-.


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