Change in temp

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melissa_dis4K
Posts: 106
Joined: Fri Sep 28, 2018 12:28 am

Change in temp

Postby melissa_dis4K » Fri Jan 25, 2019 10:36 am

I am confused on increasing and decreasing the temperature of an endothermic reaction. Why does decreasing the temperature favor the reactant? I thought that it always favored the endothermic (requiring heat) reaction.

Nicolette_Canlian_2L
Posts: 77
Joined: Fri Sep 28, 2018 12:25 am
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Re: Change in temp

Postby Nicolette_Canlian_2L » Fri Jan 25, 2019 10:49 am

Since the reaction requires heat, decreasing the temp would make it difficult for the reaction to take place. For this reason, the reaction shifts towards the reactants to form more heat necessary to carry out the reaction.

Sean Reyes 1J
Posts: 67
Joined: Fri Sep 28, 2018 12:24 am

Re: Change in temp

Postby Sean Reyes 1J » Fri Jan 25, 2019 5:52 pm

Because in an endothermic reaction, heat is used to form the product, you can essentially treat heat as a reactant. Decreasing the amount of heat means you are decreasing the amount of reactants, and thus the equilibrium would favor the direction of the reverse reaction.
Also, like already stated, this creates heat to allow the forward reaction rate to increase and then match that of the reverse reaction.

Andrew Bennecke
Posts: 62
Joined: Fri Sep 28, 2018 12:15 am

Re: Change in temp

Postby Andrew Bennecke » Fri Jan 25, 2019 7:19 pm

According to Le Chatelier's Principle, a system will always attempt to minimize the effects of a perturbation. Because of this, when the temperature is increased, it will favor the side without heat (reactants in an exothermic reaction and products in an endothermic reaction) in order to generate less heat. While there still will be a change in the Equilibrium constant after applying heat to the system, less heat is being input to the system by favoring the side of the reaction without heat.


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