Edition 7 #5.61
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chloewinnett1L
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Edition 7 #5.61
In this question, why does decreasing the amount of aqueous glucose cause a shift in the equilibrium concentration? Even though it is a product, it is technically not a gas, and I don't understand how you can include it in a K calculation.
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aisteles1G
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Re: Edition 7 #5.61
Aqueous phase reactants/products are still included in all K calculations, only liquids and solids are excluded so removing it would cause a shift to the formation of products
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Pritish Patil 1K
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Re: Edition 7 #5.61
Only liquids and solids are not included in the equilibrium expression. Aqueous and gas phase molecules are included.
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