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5.61b

Posted: Fri Jan 10, 2020 11:27 am
by JChen_2I
6CO2(g) + 6H2O(l)->C6H12O6(aq) + 6O2(g) is at equilibrium
How comes when you compress this system, there will be little to no effect on the system? Would the reaction not shift to the formation of reactants because there's less moles?

Re: 5.61b

Posted: Fri Jan 10, 2020 11:29 am
by Kaitlyn Ang 1J
I think that since you’re compressing the entire system, both the pressure of the reactants and products are increasing by the same amount, so in a sense, the ratios aren’t changing so there is little/no effect on the system.

Re: 5.61b

Posted: Sat Jan 11, 2020 3:50 pm
by 305385703
On both sides of the reaction, there are 6 moles of gas, so changing the pressure will not affect the equilibrium.

Re: 5.61b

Posted: Sun Jan 12, 2020 1:12 pm
by Noe BM 1J
You only take into account the gases, that's why when compressing the system there's no effect on the equilibrium since there is the same amount of moles of gas on both sides of the reaction.