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### changing conditions

Posted: Sun Jan 12, 2020 10:53 am
Can someone explain why taking away product leads to more product? I am just a bit confused on that topic.

### Re: changing conditions

Posted: Sun Jan 12, 2020 10:56 am
When you take away a product, the reaction needs to get back to equilibrium so it will have a net movement toward the products in order to maintain the same ratio of products and reactants at equilibrium.

Hope that helps!

### Re: changing conditions

Posted: Sun Jan 12, 2020 10:58 am
When you take away a product you are stressing the reaction and shifting it away from equilibrium. In order for it to return to equilibrium, the reaction needs to make enough product again for the reaction to return to the same equilibrium K value. Therefore, by taking away a product, the reaction now favors the product and makes more of it.

### Re: changing conditions

Posted: Sun Jan 12, 2020 11:08 am
A reaction tends to favor whatever side needs more or less "substance" to reach equilibrium. If the amount of product decreases, the reaction will favor the product side as to balance the reactants and products again.

### Re: changing conditions

Posted: Sun Jan 12, 2020 1:18 pm
Removing some of the product would decrease its concentration/partial pressure value. Mathematically the ratio [P]/[R] would be smaller. Since Q<K, the forward reaction will be favored until Q=K again

### Re: changing conditions

Posted: Sun Jan 12, 2020 5:12 pm
As explained by Dr. Lavelle, a reaction tends to favor the side that has less substance to reach equilibrium. If we take away product, the reaction will favor the products in order to balance the products and reactants or reach equilibrium.

### Re: changing conditions

Posted: Sun Jan 12, 2020 9:46 pm
The reaction will want to be balanced between the products and reactants, so there will be a shift to the products side.