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changing conditions

Posted: Sun Jan 12, 2020 10:53 am
by Sarah Blake-2I
Can someone explain why taking away product leads to more product? I am just a bit confused on that topic.

Re: changing conditions

Posted: Sun Jan 12, 2020 10:56 am
by Sanjana Munagala_1j
When you take away a product, the reaction needs to get back to equilibrium so it will have a net movement toward the products in order to maintain the same ratio of products and reactants at equilibrium.

Hope that helps!

Re: changing conditions

Posted: Sun Jan 12, 2020 10:58 am
by Deepika Reddy 1A
When you take away a product you are stressing the reaction and shifting it away from equilibrium. In order for it to return to equilibrium, the reaction needs to make enough product again for the reaction to return to the same equilibrium K value. Therefore, by taking away a product, the reaction now favors the product and makes more of it.

Re: changing conditions

Posted: Sun Jan 12, 2020 11:08 am
by Jamie Lee 1F
A reaction tends to favor whatever side needs more or less "substance" to reach equilibrium. If the amount of product decreases, the reaction will favor the product side as to balance the reactants and products again.

Re: changing conditions

Posted: Sun Jan 12, 2020 1:18 pm
by KDang_1D
Removing some of the product would decrease its concentration/partial pressure value. Mathematically the ratio [P]/[R] would be smaller. Since Q<K, the forward reaction will be favored until Q=K again

Re: changing conditions

Posted: Sun Jan 12, 2020 5:12 pm
by 205154661_Dis2J
As explained by Dr. Lavelle, a reaction tends to favor the side that has less substance to reach equilibrium. If we take away product, the reaction will favor the products in order to balance the products and reactants or reach equilibrium.

Re: changing conditions

Posted: Sun Jan 12, 2020 9:46 pm
by Ian Morris 3C
The reaction will want to be balanced between the products and reactants, so there will be a shift to the products side.