Textbook question 5J.11

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Paige Lee 1A
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Joined: Sat Sep 07, 2019 12:16 am

Textbook question 5J.11

Postby Paige Lee 1A » Mon Jan 13, 2020 1:52 pm

Could someone please explain how we know that the reaction in part B is endothermic?

GFolk_1D
Posts: 101
Joined: Fri Aug 09, 2019 12:15 am

Re: Textbook question 5J.11

Postby GFolk_1D » Mon Jan 13, 2020 2:05 pm

Yes! Because it involves the breaking of the bond between the two X molecules to form two separated X molecules we know that energy aka heat had to be put into the reaction to overcome the bond energy. Therefore it is endothermic.

Eileen Si 1G
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Re: Textbook question 5J.11

Postby Eileen Si 1G » Mon Jan 13, 2020 4:48 pm

To add on, the reaction favors the products on the right side, and we learned today in lecture that a reaction that favors the formation of products is endothermic because they require heat. On the other hand, exothermic reactions give off heat when forming products, so hearing will favor the formation of reactants instead.

Jordan Ziegler 2J
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Re: Textbook question 5J.11

Postby Jordan Ziegler 2J » Mon Jan 13, 2020 5:36 pm

Because it might be difficult to memorize whether the formation or breaking of bonds releases heat or absorbs heat, I always use this to remember: when you break a bond, you're ENDing it; this is an ENDothermic process (it absorbs heat).


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