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The question is: The four gases NH3, O2, NO, and H2O are mixed in a reaction vessel and allowed to reach equilibrium in the reaction 4 NH3(g) + 5 O2(g) <-> 4 NO(g) + 6 H2O(g). Why is there less NH3 when NO is removed?
When NO is removed, the product of the forward reaction is being decreased. In order to reach equilibrium again, the forward reaction will proceed and use the reactants to make more product. So, the reactants, including NH3, decrease as a result.
When you remove NO, the reaction favors the products because it wants to reach equilibrium. Since there is now less NO, and therefore products, the reaction proceeds forward to produce more products. This causes NH3 (reactant) to decrease.
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