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HW 5j #5

Posted: Tue Jan 14, 2020 5:18 pm
by BeylemZ-1B
Can someone explain to me why the answer to 5J#5 part D is No Change? I thought it would be the reactant favored.

Re: HW 5j #5

Posted: Tue Jan 14, 2020 5:25 pm
by Shannon Asay 1C
I'm not entirely sure why either but I'm guessing it's because the number of moles of gas on either side of the equation doesn't change so one side isn't strongly favored.

Re: HW 5j #5

Posted: Tue Jan 14, 2020 5:27 pm
by rabiasumar2E
The answer is no change because the number of moles on both the reactant and product sides are the same.

Re: HW 5j #5

Posted: Tue Jan 21, 2020 11:59 am
by BeylemZ-1B
I see now that there are two moles on the right side of the equation and 2 moles (one mole of H2 and one mole of D2), which means there is no overall change with volume change

Re: HW 5j #5

Posted: Tue Jan 21, 2020 11:33 pm
by 205291012
When there is compression, the side with fewer moles is favored. In this problem, both sides have the same number of moles so there is no change.