5j #11

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BeylemZ-1B
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5j #11

Postby BeylemZ-1B » Tue Jan 14, 2020 5:21 pm

Why would 5J.11 part b favor the products? I thought there would be no change when heating.

Shannon Asay 1C
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Re: 5j #11

Postby Shannon Asay 1C » Tue Jan 14, 2020 5:29 pm

So In 5J.11 b, the equation is X2->2X, where x is a halogen. In this equation, it is essentially breaking a bond, which means it requires energy and is endothermic. In an endothermic reaction, when you raise the temperature, the value of k increases. If k increases, that means the equilibria is favoring more of the products.

Amanda Lin 2I
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Re: 5j #11

Postby Amanda Lin 2I » Tue Jan 14, 2020 5:30 pm

Endothermic reactions favor the formation of products.

BeylemZ-1B
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Joined: Thu Jul 25, 2019 12:17 am

Re: 5j #11

Postby BeylemZ-1B » Tue Jan 21, 2020 12:00 pm

Amanda Lin 2I wrote:Endothermic reactions favor the formation of products.

I think this is too general of a statement. Endothermic reactions favor the products when the reaction is heated.

BeylemZ-1B
Posts: 95
Joined: Thu Jul 25, 2019 12:17 am

Re: 5j #11

Postby BeylemZ-1B » Tue Jan 21, 2020 12:02 pm

Shannon Asay 1C wrote:So In 5J.11 b, the equation is X2->2X, where x is a halogen. In this equation, it is essentially breaking a bond, which means it requires energy and is endothermic. In an endothermic reaction, when you raise the temperature, the value of k increases. If k increases, that means the equilibria is favoring more of the products.

So does this mean that breaking the bond if any halogen requires heat? and if there needs to be an input or heat it means it’s endothermic?


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