5J.9b

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Simon Dionson 4I
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Joined: Sat Sep 14, 2019 12:17 am

5J.9b

Postby Simon Dionson 4I » Tue Jan 14, 2020 6:40 pm

If p(NH3) is decreased will O2 increase?

3NH3 + 5O2 = 4NO + 6H2O

My initial answer is yes because the reaction will shift to the left, is this explanation correct?

MAC 4G
Posts: 121
Joined: Wed Sep 18, 2019 12:16 am

Re: 5J.9b

Postby MAC 4G » Tue Jan 14, 2020 7:22 pm

I believe so, since the pressure of O2 will increase as the reverse reaction is favored shifting .

Brooke Yasuda 2J
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Re: 5J.9b

Postby Brooke Yasuda 2J » Tue Jan 14, 2020 8:47 pm

Yes, when the partial pressure of NH3 decreases, this will cause the Q value to be smaller than K. As a result, the reaction will favor the reactants and so the O2 concentration would increase

Harry Zhang 1B
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Re: 5J.9b

Postby Harry Zhang 1B » Tue Jan 14, 2020 10:40 pm

Yes. The system will try to minimize the decrease in reactants by making the reaction to shift to the left and create more reactants when some are lost.

Caroline Beecher 2H
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Joined: Wed Nov 14, 2018 12:21 am

Re: 5J.9b

Postby Caroline Beecher 2H » Wed Jan 15, 2020 9:39 pm

Yes, when the partial pressure of NH3 is decreased in this reaction, the reverse reaction will be favored. This will cause and increase in partial pressure for O2 as it is part of the reactants and will increase when the reaction shifts to the left.

Caroline Beecher 2H
Posts: 51
Joined: Wed Nov 14, 2018 12:21 am

Re: 5J.9b

Postby Caroline Beecher 2H » Wed Jan 15, 2020 9:39 pm

Yes, when the partial pressure of NH3 is decreased in this reaction, the reverse reaction will be favored. This will cause and increase in partial pressure for O2 as it is part of the reactants and will increase when the reaction shifts to the left.

Edmund Zhi 2B
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Re: 5J.9b

Postby Edmund Zhi 2B » Sat Jan 18, 2020 1:36 pm

I like to think of this mathematically in terms of the equilibrium constant. Because a number in the denominator is decreasing, O2, which is also in the denominator, must increase to compensate for this to maintain the same K.

Sofia Barker 2C
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Re: 5J.9b

Postby Sofia Barker 2C » Sun Jan 19, 2020 12:08 pm

Yes, the reverse reaction will be favored so as to bring the reaction back to equilibrium by increasing the pressure of the other reactant.

Emily Vainberg 1D
Posts: 102
Joined: Sat Jul 20, 2019 12:15 am

Re: 5J.9b

Postby Emily Vainberg 1D » Sun Jan 19, 2020 12:44 pm

Since there are more moles on the right, this change will cause the reaction to shift left and increase the partial pressure of 02


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