percent ionization

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percent ionization

Postby 205389184 » Sun Jan 26, 2020 7:57 pm

Why does a small percentage of initial make the approximation acceptable?

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Re: percent ionization

Postby AngieGarcia_4F » Sun Jan 26, 2020 7:59 pm

Because you are subtracting a very minuscule amount from a much larger initial amount so the subtraction becomes negligible. Like if I have $10,000 and I give away $1 I would basically still have $10,000.

Christine Honda 2I
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Re: percent ionization

Postby Christine Honda 2I » Sun Jan 26, 2020 8:00 pm

The small percent ionization indicates the change in molar concentration or x is so small that it becomes negligible and this makes the approximation acceptable.

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Re: percent ionization

Postby KarineKim2L » Sun Jan 26, 2020 8:01 pm

If X is less than 5% of the initial concentration, then the equilibrium concentration will not differ very much from the final even if you subtracted X. (Initial - X) would be close enough to just using the Initial concentration for the equilibrium concentration and therefore we can basically ignore the minus X portion.

Jasmine 2C
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Re: percent ionization

Postby Jasmine 2C » Sun Jan 26, 2020 8:05 pm

a small percentage indicates that a very very minute amount of reactant had donated a proton; a very very minute amount could mean 0.00000001, and from ICE boxes, subtracting that very small value by, say, 0.1, would make essentially no difference. So approximating 0.1-x to 0.1 is perfectly fine

Anish Natarajan 4G
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Re: percent ionization

Postby Anish Natarajan 4G » Sun Jan 26, 2020 8:16 pm

If you have a small percentage of the initial then that means that the change is negligible so if you have something in the denominator like .01-(8*10^-9) that's pretty much the same thing as .01

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