HCl and NaOH producing dT

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WGaines_2E
Posts: 47
Joined: Mon Nov 18, 2019 12:18 am

HCl and NaOH producing dT

Postby WGaines_2E » Mon Mar 09, 2020 9:28 pm

Which of the following combinations of HCl and NaOH produce the largest dT?
a)50mL of 1M HCl and 50mL of 1M NaOH
b)50mL of 2M HCl and 50mL of 2M NaOH
c)100mL of 1M HCl and 50mL of 2M NaOH
d)100mL of 1M HCl and 100mL of 1M NaOH

is the answer b or c?

chemboi
Posts: 101
Joined: Sat Jul 20, 2019 12:16 am

Re: HCl and NaOH producing dT

Postby chemboi » Mon Mar 09, 2020 9:38 pm

I think its B because while you have equal number of reactant molecules, the reaction will be taking place in less volume of solution, so any temperature change will be more pronounced.

Jessa Maheras 4F
Posts: 121
Joined: Fri Aug 02, 2019 12:16 am

Re: HCl and NaOH producing dT

Postby Jessa Maheras 4F » Wed Mar 11, 2020 7:12 pm

I believe it would be B because there is a greater concentration of reactants colliding! Because there are more reactants colliding, more energy will be released and a larger dT will result. :)

William Chan 1D
Posts: 102
Joined: Sat Sep 14, 2019 12:15 am

Re: HCl and NaOH producing dT

Postby William Chan 1D » Wed Mar 11, 2020 10:23 pm

The answer would be b. The amount of mols HCL and NaOH reacting would is the highest in this problem, as well as the lowest volume of liquid. Because there is less liquid in the beaker, the temperature difference would be higher.

Bryan Chen 1H
Posts: 58
Joined: Mon Jun 17, 2019 7:24 am

Re: HCl and NaOH producing dT

Postby Bryan Chen 1H » Wed Mar 11, 2020 10:28 pm

since mols are the same for each, I looked at volume of soln. where the delta temp change is greatest in the smallest volume. I thought of the soln volume like an absorbant, so the more water there is, the less a rxn will be able to shift its temp as compared to a little volume of water


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